单指数模型计算例题
@成享1813：一道简单的关于指数函数的计算题,求解,求过程 -
贲育15115435874…… (5/6a^(1/3)b^(-2)·(-3a^(-1/2)b^(-1)/[(4a^(2/3)b^(-3)·√ab =[(5/6)·(-3)/4]·a^(1/3-1/2-2/3+1/2)·b^(-2-1+3+1/2) =-5/8·a^(-1/3)·b^0.5 =-5√b/(8³√a) =-5³√a²√b/(8a)
贲育15115435874…… (5/6a^(1/3)b^(-2)·(-3a^(-1/2)b^(-1)/[(4a^(2/3)b^(-3)·√ab =[(5/6)·(-3)/4]·a^(1/3-1/2-2/3+1/2)·b^(-2-1+3+1/2) =-5/8·a^(-1/3)·b^0.5 =-5√b/(8³√a) =-5³√a²√b/(8a)
