将百分制成绩转换为五级制
@黎栋791:将百分制成绩转化为优秀、良好、中等、及格和不及格的5级制成绩 -
徒燕19221699824…… 你好,程序如下: (Java写的) import java.io.*; public class ChengjiPanduan { public static void main(String[] args) throws Exception { BufferedReader bf=new BufferedReader(new InputStreamReader(System.in)); System.out.println("请输入...
@黎栋791:用VB编程 输入一个百分制成绩,把它转换成五级记分制 -
徒燕19221699824…… Private Sub Command1_Click() Dim n As Single Dim s As String n = Val(InputBox("请你输入成绩")) Select Case n Case 90 To 100 s = "优秀" Case 80 To 90 s = "良" Case 70 To 80 s = "中" Case 60 To 70 s = "及格" Case 0 To 60 s = "不及格" Case Else s = "请你输入0至100自己的数字" End Select MsgBox s End Sub
@黎栋791:python中怎么利用while true将百分制成绩转化成五等级,并且按负数或大于100退出循环? -
徒燕19221699824…… #!/usr/bin/python3 # -*- coding:utf-8 -*- # @Time :2021/4/02 08:35 def getlevel(fraction): if 90 <= fraction <= 100: return "A" elif 80 <= fraction < 90: return "B" elif 70 <= fraction < 80: return "C" elif 60 <= fraction < 70: return "D" else: ...
@黎栋791:C语言帮忙写代码根据用户输入的成绩,将一个百分制的成绩转化为5个等级:90分以上为'A',80~89分为'B',70~79分为'C',60~69分为'D',60分一... - 作业帮
徒燕19221699824…… [答案] #include void main(){int a;printf("input scale:");scanf("%d",&a);a/=10;switch(a){case 10:case 9:printf("A\n");break;case 8:printf("B\n");break;case 7:printf("C\n");break;case 6:printf("D\n");break;def...
@黎栋791:设计一个程序,将从键盘上输入的百分制成绩转换成对应的五分制成绩并输出.90分以上为A,80~90分为B,70~79分为C,60~69分为D,60分以下为E.分别用条件... - 作业帮
徒燕19221699824…… [答案] #include int main(){\x09\x09int a,t;\x09scanf("%d",&a);\x09if(a100)\x09\x09printf("输入有误!\n");\x09else\x09{\x09\x09if(a>=90)\x09\x09\x09t=1;\x09\x09else if(a>=80&&a=70&&a=60&&a
@黎栋791:c语言百分制成绩成绩转换为5级分制调用函数实现,并写出完整的函数借口(函数编程练习) -
徒燕19221699824…… #include "iostream.h" main() { int a=0,b=0,c=0; int n=0; int i; int score=0; printf("请输入人数:\n"); scanf("%d",&n); printf("请输入所有人成绩\n",n); for(i=0;i<n;i++) { scanf("%d",&score); if(score>=70) if(score<=79) c++; else if(...
@黎栋791:请高手 帮忙做一道c语言题 编程,把百分制成绩转换成5级记分制,要求用switch语句. 90分以上(包括90): -
徒燕19221699824…… #include "stdio.h" #include "stdlib.h" int main() { int score,level; char band; printf("Input Score:"); scanf("%d",&score); level=score/10; switch(level) { case 10: case 9: band='A'; break; case 8: band='B'; break; case 7: band='C'; ...
@黎栋791:百分制成绩表转换五级制成绩表,怎么做 -
徒燕19221699824…… 先将百分制的值除以20,然后再四舍五入,就可以得到对应的等级了.
@黎栋791:用VB将学生成绩百分制转换为五级制. -
徒燕19221699824…… private sub command1_click() dim n as single dim s as string n = val(inputbox("请你输入成绩")) select case n case 90 to 100 s = "优秀" case 80 to 90 s = "良" case 70 to 80 s = "中" case 60 to 70 s = "及格" case 0 to 60 s = "不及格" case else s = "请你输入0至100自己的数字" end select msgbox s end sub
@黎栋791:输入一个百分制分数,输出对应的五级计分等级的 C语言程序
徒燕19221699824…… int level = 0; cin >> level; int newLevel; if(level<0 || level>100) { newLevel = 0; } else { newLevel = (level-1)/20+1; } switch (newLevel) { case 1: cout << newLevel; break; case 2: cout << newLevel; break; case 3: cout << newLevel; ...
徒燕19221699824…… 你好,程序如下: (Java写的) import java.io.*; public class ChengjiPanduan { public static void main(String[] args) throws Exception { BufferedReader bf=new BufferedReader(new InputStreamReader(System.in)); System.out.println("请输入...
@黎栋791:用VB编程 输入一个百分制成绩,把它转换成五级记分制 -
徒燕19221699824…… Private Sub Command1_Click() Dim n As Single Dim s As String n = Val(InputBox("请你输入成绩")) Select Case n Case 90 To 100 s = "优秀" Case 80 To 90 s = "良" Case 70 To 80 s = "中" Case 60 To 70 s = "及格" Case 0 To 60 s = "不及格" Case Else s = "请你输入0至100自己的数字" End Select MsgBox s End Sub
@黎栋791:python中怎么利用while true将百分制成绩转化成五等级,并且按负数或大于100退出循环? -
徒燕19221699824…… #!/usr/bin/python3 # -*- coding:utf-8 -*- # @Time :2021/4/02 08:35 def getlevel(fraction): if 90 <= fraction <= 100: return "A" elif 80 <= fraction < 90: return "B" elif 70 <= fraction < 80: return "C" elif 60 <= fraction < 70: return "D" else: ...
@黎栋791:C语言帮忙写代码根据用户输入的成绩,将一个百分制的成绩转化为5个等级:90分以上为'A',80~89分为'B',70~79分为'C',60~69分为'D',60分一... - 作业帮
徒燕19221699824…… [答案] #include void main(){int a;printf("input scale:");scanf("%d",&a);a/=10;switch(a){case 10:case 9:printf("A\n");break;case 8:printf("B\n");break;case 7:printf("C\n");break;case 6:printf("D\n");break;def...
@黎栋791:设计一个程序,将从键盘上输入的百分制成绩转换成对应的五分制成绩并输出.90分以上为A,80~90分为B,70~79分为C,60~69分为D,60分以下为E.分别用条件... - 作业帮
徒燕19221699824…… [答案] #include int main(){\x09\x09int a,t;\x09scanf("%d",&a);\x09if(a100)\x09\x09printf("输入有误!\n");\x09else\x09{\x09\x09if(a>=90)\x09\x09\x09t=1;\x09\x09else if(a>=80&&a=70&&a=60&&a
@黎栋791:c语言百分制成绩成绩转换为5级分制调用函数实现,并写出完整的函数借口(函数编程练习) -
徒燕19221699824…… #include "iostream.h" main() { int a=0,b=0,c=0; int n=0; int i; int score=0; printf("请输入人数:\n"); scanf("%d",&n); printf("请输入所有人成绩\n",n); for(i=0;i<n;i++) { scanf("%d",&score); if(score>=70) if(score<=79) c++; else if(...
@黎栋791:请高手 帮忙做一道c语言题 编程,把百分制成绩转换成5级记分制,要求用switch语句. 90分以上(包括90): -
徒燕19221699824…… #include "stdio.h" #include "stdlib.h" int main() { int score,level; char band; printf("Input Score:"); scanf("%d",&score); level=score/10; switch(level) { case 10: case 9: band='A'; break; case 8: band='B'; break; case 7: band='C'; ...
@黎栋791:百分制成绩表转换五级制成绩表,怎么做 -
徒燕19221699824…… 先将百分制的值除以20,然后再四舍五入,就可以得到对应的等级了.
@黎栋791:用VB将学生成绩百分制转换为五级制. -
徒燕19221699824…… private sub command1_click() dim n as single dim s as string n = val(inputbox("请你输入成绩")) select case n case 90 to 100 s = "优秀" case 80 to 90 s = "良" case 70 to 80 s = "中" case 60 to 70 s = "及格" case 0 to 60 s = "不及格" case else s = "请你输入0至100自己的数字" end select msgbox s end sub
@黎栋791:输入一个百分制分数,输出对应的五级计分等级的 C语言程序
徒燕19221699824…… int level = 0; cin >> level; int newLevel; if(level<0 || level>100) { newLevel = 0; } else { newLevel = (level-1)/20+1; } switch (newLevel) { case 1: cout << newLevel; break; case 2: cout << newLevel; break; case 3: cout << newLevel; ...