将百分制转换成五级制视频
@扈咐6861：百分制成绩表转换五级制成绩表,怎么做 -
蒋舍18710792300…… 先将百分制的值除以20,然后再四舍五入,就可以得到对应的等级了.
@扈咐6861：用VB编程 输入一个百分制成绩,把它转换成五级记分制 -
蒋舍18710792300…… Private Sub Command1_Click() Dim n As Single Dim s As String n = Val(InputBox(＂请你输入成绩＂)) Select Case n Case 90 To 100 s = ＂优秀＂ Case 80 To 90 s = ＂良＂ Case 70 To 80 s = ＂中＂ Case 60 To 70 s = ＂及格＂ Case 0 To 60 s = ＂不及格＂ Case Else s = ＂请你输入0至100自己的数字＂ End Select MsgBox s End Sub
@扈咐6861：将百分制成绩转化为优秀、良好、中等、及格和不及格的5级制成绩 -
蒋舍18710792300…… 你好,程序如下: (Java写的) import java.io.*; public class ChengjiPanduan { public static void main(String[] args) throws Exception { BufferedReader bf=new BufferedReader(new InputStreamReader(System.in)); System.out.println(＂请输入...
@扈咐6861：python中怎么利用while true将百分制成绩转化成五等级,并且按负数或大于100退出循环? -
蒋舍18710792300…… #!/usr/bin/python3 # -*- coding:utf-8 -*- # @Time :2021/4/02 08:35 def getlevel(fraction): if 90 <= fraction <= 100: return ＂A＂ elif 80 <= fraction < 90: return ＂B＂ elif 70 <= fraction < 80: return ＂C＂ elif 60 <= fraction < 70: return ＂D＂ else: ...
@扈咐6861：c语言百分制成绩成绩转换为5级分制调用函数实现,并写出完整的函数借口(函数编程练习) -
蒋舍18710792300…… #include ＂iostream.h＂ main() { int a=0,b=0,c=0; int n=0; int i; int score=0; printf(＂请输入人数:\n＂); scanf(＂%d＂,&n); printf(＂请输入所有人成绩\n＂,n); for(i=0;i<n;i++) { scanf(＂%d＂,&score); if(score>=70) if(score<=79) c++; else if(...
@扈咐6861：输入一个百分制分数,输出对应的五级计分等级的 C语言程序
蒋舍18710792300…… int level = 0; cin >> level; int newLevel; if(level<0 || level>100) { newLevel = 0; } else { newLevel = (level-1)/20+1; } switch (newLevel) { case 1: cout << newLevel; break; case 2: cout << newLevel; break; case 3: cout << newLevel; ...
@扈咐6861：给出一百分制成绩 C语言程序 -
蒋舍18710792300…… 这是一个C++程序,你看一下,和C语言差不多的! //Example 2-2 :将百分制的分数转换为5级制分数 #include <iostream.h> int main() { int old_grade,new_grade; cout<<＂Please input the score:＂; cin>>old_grade; switch(old_grade/10) { case ...
@扈咐6861：请高手 帮忙做一道c语言题 编程,把百分制成绩转换成5级记分制,要求用switch语句. 90分以上(包括90): -
蒋舍18710792300…… #include ＂stdio.h＂ #include ＂stdlib.h＂ int main() { int score,level; char band; printf(＂Input Score:＂); scanf(＂%d＂,&score); level=score/10; switch(level) { case 10: case 9: band='A'; break; case 8: band='B'; break; case 7: band='C'; ...
@扈咐6861：用VB将学生成绩百分制转换为五级制. -
蒋舍18710792300…… private sub command1_click() dim n as single dim s as string n = val(inputbox(＂请你输入成绩＂)) select case n case 90 to 100 s = ＂优秀＂ case 80 to 90 s = ＂良＂ case 70 to 80 s = ＂中＂ case 60 to 70 s = ＂及格＂ case 0 to 60 s = ＂不及格＂ case else s = ＂请你输入0至100自己的数字＂ end select msgbox s end sub
@扈咐6861：C++百分制转五分制
蒋舍18710792300…… #include<iostream> using namespace std; int main() { for(int i = 0; i < 5; i++) { double tmp; cin>>tmp; if(tmp > 100 && tmp < 0) cout<<＂Wrong grade!＂<<endl; else if(tmp < 60) cout<<'E'; else if(tmp >= 60 && tmp < 70) cout<<'D'; else if(tmp >= 70 &...
蒋舍18710792300…… 先将百分制的值除以20,然后再四舍五入,就可以得到对应的等级了.
@扈咐6861：用VB编程 输入一个百分制成绩,把它转换成五级记分制 -
蒋舍18710792300…… Private Sub Command1_Click() Dim n As Single Dim s As String n = Val(InputBox(＂请你输入成绩＂)) Select Case n Case 90 To 100 s = ＂优秀＂ Case 80 To 90 s = ＂良＂ Case 70 To 80 s = ＂中＂ Case 60 To 70 s = ＂及格＂ Case 0 To 60 s = ＂不及格＂ Case Else s = ＂请你输入0至100自己的数字＂ End Select MsgBox s End Sub
@扈咐6861：将百分制成绩转化为优秀、良好、中等、及格和不及格的5级制成绩 -
蒋舍18710792300…… 你好,程序如下: (Java写的) import java.io.*; public class ChengjiPanduan { public static void main(String[] args) throws Exception { BufferedReader bf=new BufferedReader(new InputStreamReader(System.in)); System.out.println(＂请输入...
@扈咐6861：python中怎么利用while true将百分制成绩转化成五等级,并且按负数或大于100退出循环? -
蒋舍18710792300…… #!/usr/bin/python3 # -*- coding:utf-8 -*- # @Time :2021/4/02 08:35 def getlevel(fraction): if 90 <= fraction <= 100: return ＂A＂ elif 80 <= fraction < 90: return ＂B＂ elif 70 <= fraction < 80: return ＂C＂ elif 60 <= fraction < 70: return ＂D＂ else: ...
@扈咐6861：c语言百分制成绩成绩转换为5级分制调用函数实现,并写出完整的函数借口(函数编程练习) -
蒋舍18710792300…… #include ＂iostream.h＂ main() { int a=0,b=0,c=0; int n=0; int i; int score=0; printf(＂请输入人数:\n＂); scanf(＂%d＂,&n); printf(＂请输入所有人成绩\n＂,n); for(i=0;i<n;i++) { scanf(＂%d＂,&score); if(score>=70) if(score<=79) c++; else if(...
@扈咐6861：输入一个百分制分数,输出对应的五级计分等级的 C语言程序
蒋舍18710792300…… int level = 0; cin >> level; int newLevel; if(level<0 || level>100) { newLevel = 0; } else { newLevel = (level-1)/20+1; } switch (newLevel) { case 1: cout << newLevel; break; case 2: cout << newLevel; break; case 3: cout << newLevel; ...
@扈咐6861：给出一百分制成绩 C语言程序 -
蒋舍18710792300…… 这是一个C++程序,你看一下,和C语言差不多的! //Example 2-2 :将百分制的分数转换为5级制分数 #include <iostream.h> int main() { int old_grade,new_grade; cout<<＂Please input the score:＂; cin>>old_grade; switch(old_grade/10) { case ...
@扈咐6861：请高手 帮忙做一道c语言题 编程,把百分制成绩转换成5级记分制,要求用switch语句. 90分以上(包括90): -
蒋舍18710792300…… #include ＂stdio.h＂ #include ＂stdlib.h＂ int main() { int score,level; char band; printf(＂Input Score:＂); scanf(＂%d＂,&score); level=score/10; switch(level) { case 10: case 9: band='A'; break; case 8: band='B'; break; case 7: band='C'; ...
@扈咐6861：用VB将学生成绩百分制转换为五级制. -
蒋舍18710792300…… private sub command1_click() dim n as single dim s as string n = val(inputbox(＂请你输入成绩＂)) select case n case 90 to 100 s = ＂优秀＂ case 80 to 90 s = ＂良＂ case 70 to 80 s = ＂中＂ case 60 to 70 s = ＂及格＂ case 0 to 60 s = ＂不及格＂ case else s = ＂请你输入0至100自己的数字＂ end select msgbox s end sub
@扈咐6861：C++百分制转五分制
蒋舍18710792300…… #include<iostream> using namespace std; int main() { for(int i = 0; i < 5; i++) { double tmp; cin>>tmp; if(tmp > 100 && tmp < 0) cout<<＂Wrong grade!＂<<endl; else if(tmp < 60) cout<<'E'; else if(tmp >= 60 && tmp < 70) cout<<'D'; else if(tmp >= 70 &...
