柚子猫cos原神
@国贝5039：求求求:我很喜欢你txt百度云,非常感谢╰(*︶`*)╯,柚子猫的! -
魏媛13554749053…… 链接:https://pan.baidu.com/s/1g4GQ747qYwm26I_kgKEQaA 密码:zq7i
@国贝5039：化tan( - 330°)tan420°cos390°cos1140°sin750° -
魏媛13554749053…… 解:tan(-330°)tan420°cos390°cos1140°sin750°=tan(30°)tan(60°)cos(30°)cos(60°)sin(30°)=cos(30°)cos(60°)sin(30°)=sin(60°)cos(60°)sin(30°)=0.5sin(120°)sin(30°)=0.5sin(60°)x0.5=0.25x√(3)÷2=0.25x0.5x√3=0.125√(3)=8分之√(3)
@国贝5039：糖心有哪些cos网红 -
魏媛13554749053…… 糖心中有YuzuKitty这位COSER.YuzuKitty是糖心APP的COSER,二次元动漫博主,2020年4月出道,在糖心app直播.
@国贝5039：sin67°cos22° - sin23°cos68°=
魏媛13554749053…… sin67°cos22°-sin23°cos68°=sin67°sin68°-cos67°cos68°=-cos(67°+68°)=-cos(135°)=-√2/2
@国贝5039：α∈( - π/2,0)cosα=4/5 tan2α= -
魏媛13554749053…… ∵ α∈(-π/2,0),cosα=4/5 ∴sinα = -√(1-cos²α) = -√{1-(4/5)²} = -3/5 ∴sin2α=2sinαcosα = 2*(-3/5)*(4/5) = -24/25 cos2α=2cos²α-1 = 2*(4/5)²-1 = 7/25 ∴tan2α=sin2α/cos2α = (7/25)/(-24/25) = -7/24
@国贝5039：求sin²10°+sin²20°+sin²40°+sin²50°+sin²70°+sin²80° -
魏媛13554749053…… 你好,解答如下: sin²10°+sin²20°+sin²40°+sin²50°+sin²70°+sin²80° =cos²80° + cos²70° + cos²50° + sin²50°+sin²70°+sin²80° = 3
@国贝5039：当X趋向于1时 lim<(1 - X)*tanπX/2>解题过程 -
魏媛13554749053…… =lim y*tan(π/2+πy/2) =lim y*[-cot(πy/2)],∵tan(x+π/2)=-cotx =-lim y/sin(πy/2)*cos(πy/2) =-lim (yπ/2)/sin(πy/2)*1/(2/π)*cos(πy/2) =-(2/π)*(1)*(1) =-2/π
@国贝5039：f(x)=sin(平方)+根号3cosXsinX+2cos(平方)x,X属于R -
魏媛13554749053…… f(x)=sin²x+√3sinxcosx+2cos²x =√3sinxcosx+cos²x+1 =(√3/2)sin2x+(1/2)[cos2x+1)+1 =(√3/2)sin2x+(1/2)cos2x+(3/2) =sin(2x+π/6)+(3/2) 最小正周期是2π/2=π 增区间是:2kπ-π/2≤2x+π/6≤2kπ+π/2 即:kπ-π/3≤x≤kπ+π/6 得增区间是:[kπ-π/3,kπ+π/6],其中k∈Z
@国贝5039：cos - 165°怎么求?注意是负的 - 作业帮
魏媛13554749053…… [答案] cos-165°=cos165°=-cos15°=-cos(45°-30°) =-cos45°cos30°-sin45°sin30° =-√2/2*√3/2-√2/2*1/2 =-(√2+√6)/4
魏媛13554749053…… 链接:https://pan.baidu.com/s/1g4GQ747qYwm26I_kgKEQaA 密码:zq7i
@国贝5039：化tan( - 330°)tan420°cos390°cos1140°sin750° -
魏媛13554749053…… 解:tan(-330°)tan420°cos390°cos1140°sin750°=tan(30°)tan(60°)cos(30°)cos(60°)sin(30°)=cos(30°)cos(60°)sin(30°)=sin(60°)cos(60°)sin(30°)=0.5sin(120°)sin(30°)=0.5sin(60°)x0.5=0.25x√(3)÷2=0.25x0.5x√3=0.125√(3)=8分之√(3)
@国贝5039：糖心有哪些cos网红 -
魏媛13554749053…… 糖心中有YuzuKitty这位COSER.YuzuKitty是糖心APP的COSER,二次元动漫博主,2020年4月出道,在糖心app直播.
@国贝5039：sin67°cos22° - sin23°cos68°=
魏媛13554749053…… sin67°cos22°-sin23°cos68°=sin67°sin68°-cos67°cos68°=-cos(67°+68°)=-cos(135°)=-√2/2
@国贝5039：α∈( - π/2,0)cosα=4/5 tan2α= -
魏媛13554749053…… ∵ α∈(-π/2,0),cosα=4/5 ∴sinα = -√(1-cos²α) = -√{1-(4/5)²} = -3/5 ∴sin2α=2sinαcosα = 2*(-3/5)*(4/5) = -24/25 cos2α=2cos²α-1 = 2*(4/5)²-1 = 7/25 ∴tan2α=sin2α/cos2α = (7/25)/(-24/25) = -7/24
@国贝5039：求sin²10°+sin²20°+sin²40°+sin²50°+sin²70°+sin²80° -
魏媛13554749053…… 你好,解答如下: sin²10°+sin²20°+sin²40°+sin²50°+sin²70°+sin²80° =cos²80° + cos²70° + cos²50° + sin²50°+sin²70°+sin²80° = 3
@国贝5039：当X趋向于1时 lim<(1 - X)*tanπX/2>解题过程 -
魏媛13554749053…… =lim y*tan(π/2+πy/2) =lim y*[-cot(πy/2)],∵tan(x+π/2)=-cotx =-lim y/sin(πy/2)*cos(πy/2) =-lim (yπ/2)/sin(πy/2)*1/(2/π)*cos(πy/2) =-(2/π)*(1)*(1) =-2/π
@国贝5039：f(x)=sin(平方)+根号3cosXsinX+2cos(平方)x,X属于R -
魏媛13554749053…… f(x)=sin²x+√3sinxcosx+2cos²x =√3sinxcosx+cos²x+1 =(√3/2)sin2x+(1/2)[cos2x+1)+1 =(√3/2)sin2x+(1/2)cos2x+(3/2) =sin(2x+π/6)+(3/2) 最小正周期是2π/2=π 增区间是:2kπ-π/2≤2x+π/6≤2kπ+π/2 即:kπ-π/3≤x≤kπ+π/6 得增区间是:[kπ-π/3,kπ+π/6],其中k∈Z
@国贝5039：cos - 165°怎么求?注意是负的 - 作业帮
魏媛13554749053…… [答案] cos-165°=cos165°=-cos15°=-cos(45°-30°) =-cos45°cos30°-sin45°sin30° =-√2/2*√3/2-√2/2*1/2 =-(√2+√6)/4
