a+hero+in+my+heart
@涂群1588：英语作文 A 'Hero' in my eyes (60个单词左右.适合初二的) - 作业帮
鲜怡14736031007…… [答案] My father is always a hero inmy eyes.My father is a general in the people's liberation army.He is a four stars general.During the peace time,he is involves in the rescuse work in any natural disasters,like the flood,and earth quake.He is very smart in his ...
@涂群1588：A hero in my heart -
鲜怡14736031007…… A hero in my heart 1. Everyone's heart have a hero,maybe a person who save the people,maybe a animal who have got good spirit. So far,I can't forget a person who helped plenty of people.His name is Leifeng.I think he was a good person I can't ...
@涂群1588：e的x次方 - lnx的最小值大于等于(a - 1)x+lna求a的范围 -
鲜怡14736031007…… 首先,我们可以对于 $e^{x} - \ln(x)$ 求导数:$$\frac{d}{dx}(e^{x} - \ln(x)) = e^{x} - \frac{1}{x}$$令导数等于 $0$,可以得到:$$e^{x} = \frac{1}{x}$$求解上式,可以得到 $x = 1$.因此,$e^{x} - \ln(x)$ 在 $x=1$ 处取得最小值.现在,我们需要证明:$...
@涂群1588：把五个元音字母变成各种单词 例:A+N(AN)+D(AND)+H(HAND) -
鲜怡14736031007…… A+T(AT)+H(HAT)+T(THAT) E+H(HE)+R(HER)+O(HERO)
@涂群1588：用c 语言,还有编程计算a+aa+aaa+…+aa…a〔n个a〕的值,n个a的值由键盘输入 -
鲜怡14736031007…… #include<stdio.h>#include<math.h> void main() { int a,n,sum=0,temp=0; printf(＂input the a and n:\n＂); scanf(＂%d%d＂,&a,&n); printf(＂sum=＂); for(int i=1;i<=n;i++) { for(int j=1;j<=i;j++) temp+=a*pow(10,j-1); sum+=temp; if(i==n) //cout<<temp<<...
@涂群1588：编写程序,由用户输入a和n的值,求a+aa+aaa+…+aa…a(n个a)之和,要求调用自定义函 -
鲜怡14736031007…… 参考代码如下: #include<stdio.h> long func(int a, int n) { int i; long s=0,t=1; for(i=1;i<=n;++i){ s+=t*a; t=t*10+1; } return s; } int main() { int n,a; scanf(＂%d%d＂,&a,&n); printf(＂%ld＂,func(a,n)); return 0; }
@涂群1588：定语从句专练 -
鲜怡14736031007…… 定语从句 1. The man ____ visited our school yesterday is from London. A. who B. which C. whom D. when2. The woman ____ is talking to my...
@涂群1588：c语言问题:求a+aa+aaa+aaaa+aaaaa的值,其中a是0 - 9中的一个数 -
鲜怡14736031007…… #include<stdio.h> main() { int n,i; float sum=0,temp=1; printf(＂please input a\n＂); scanf(＂%d＂,&n); for(i=0;i<n;i++) { temp*=10; /* temp等于10的i+1次方,temp最后等于10的n次方 */ sum+=(temp-1)/9*2; /* 2等于(10减1)除以9再乘以2,其它的照推22=(100-1)/9*2 */ } printf(＂the sum is %f\n＂,sum); getchar(); getchar(); /*本程序假设n>0,楼主可自己加语句限制n的输入*/ }
@涂群1588：C语言编程 求a+aa+aaa+aaaa+………的值,直到加到n个a那一项,其中a是一个数字,n表示a的位数. -
鲜怡14736031007…… #include＂stdio.h＂ void main() { int a,n,t,i; long int s=0; printf(＂请输入一个0-9的数字,再输入任意一个整数\n＂); scanf(＂%d%d＂,&a,&n); t=a; for(i=1;i<=n;i++) { s=s+a; a=a*10+t; } printf(＂和为%ld\n＂,s); }
@涂群1588：C语言.编程计算a+aa+aaa+……+aa…a(n个a)的值,要求n和a由用户从键盘输入. 假设输入2和3 输出246 -
鲜怡14736031007…… a值应该不能动的,要不你原来的a值就没了 循环前加个 t=a 循环里改下 s+=a; 改成 s+=t; t=t*10+1; 改成 t=t*10+a; a=a*t; 这步直接去掉 我学的其他编程,不过这个还是能看懂,你最好注意下在n的值比较大的时候int范围会不会超出
鲜怡14736031007…… [答案] My father is always a hero inmy eyes.My father is a general in the people's liberation army.He is a four stars general.During the peace time,he is involves in the rescuse work in any natural disasters,like the flood,and earth quake.He is very smart in his ...
@涂群1588：A hero in my heart -
鲜怡14736031007…… A hero in my heart 1. Everyone's heart have a hero,maybe a person who save the people,maybe a animal who have got good spirit. So far,I can't forget a person who helped plenty of people.His name is Leifeng.I think he was a good person I can't ...
@涂群1588：e的x次方 - lnx的最小值大于等于(a - 1)x+lna求a的范围 -
鲜怡14736031007…… 首先,我们可以对于 $e^{x} - \ln(x)$ 求导数:$$\frac{d}{dx}(e^{x} - \ln(x)) = e^{x} - \frac{1}{x}$$令导数等于 $0$,可以得到:$$e^{x} = \frac{1}{x}$$求解上式,可以得到 $x = 1$.因此,$e^{x} - \ln(x)$ 在 $x=1$ 处取得最小值.现在,我们需要证明:$...
@涂群1588：把五个元音字母变成各种单词 例:A+N(AN)+D(AND)+H(HAND) -
鲜怡14736031007…… A+T(AT)+H(HAT)+T(THAT) E+H(HE)+R(HER)+O(HERO)
@涂群1588：用c 语言,还有编程计算a+aa+aaa+…+aa…a〔n个a〕的值,n个a的值由键盘输入 -
鲜怡14736031007…… #include<stdio.h>#include<math.h> void main() { int a,n,sum=0,temp=0; printf(＂input the a and n:\n＂); scanf(＂%d%d＂,&a,&n); printf(＂sum=＂); for(int i=1;i<=n;i++) { for(int j=1;j<=i;j++) temp+=a*pow(10,j-1); sum+=temp; if(i==n) //cout<<temp<<...
@涂群1588：编写程序,由用户输入a和n的值,求a+aa+aaa+…+aa…a(n个a)之和,要求调用自定义函 -
鲜怡14736031007…… 参考代码如下: #include<stdio.h> long func(int a, int n) { int i; long s=0,t=1; for(i=1;i<=n;++i){ s+=t*a; t=t*10+1; } return s; } int main() { int n,a; scanf(＂%d%d＂,&a,&n); printf(＂%ld＂,func(a,n)); return 0; }
@涂群1588：定语从句专练 -
鲜怡14736031007…… 定语从句 1. The man ____ visited our school yesterday is from London. A. who B. which C. whom D. when2. The woman ____ is talking to my...
@涂群1588：c语言问题:求a+aa+aaa+aaaa+aaaaa的值,其中a是0 - 9中的一个数 -
鲜怡14736031007…… #include<stdio.h> main() { int n,i; float sum=0,temp=1; printf(＂please input a\n＂); scanf(＂%d＂,&n); for(i=0;i<n;i++) { temp*=10; /* temp等于10的i+1次方,temp最后等于10的n次方 */ sum+=(temp-1)/9*2; /* 2等于(10减1)除以9再乘以2,其它的照推22=(100-1)/9*2 */ } printf(＂the sum is %f\n＂,sum); getchar(); getchar(); /*本程序假设n>0,楼主可自己加语句限制n的输入*/ }
@涂群1588：C语言编程 求a+aa+aaa+aaaa+………的值,直到加到n个a那一项,其中a是一个数字,n表示a的位数. -
鲜怡14736031007…… #include＂stdio.h＂ void main() { int a,n,t,i; long int s=0; printf(＂请输入一个0-9的数字,再输入任意一个整数\n＂); scanf(＂%d%d＂,&a,&n); t=a; for(i=1;i<=n;i++) { s=s+a; a=a*10+t; } printf(＂和为%ld\n＂,s); }
@涂群1588：C语言.编程计算a+aa+aaa+……+aa…a(n个a)的值,要求n和a由用户从键盘输入. 假设输入2和3 输出246 -
鲜怡14736031007…… a值应该不能动的,要不你原来的a值就没了 循环前加个 t=a 循环里改下 s+=a; 改成 s+=t; t=t*10+1; 改成 t=t*10+a; a=a*t; 这步直接去掉 我学的其他编程,不过这个还是能看懂,你最好注意下在n的值比较大的时候int范围会不会超出
