her+name+is+candy

@邱有4885:一 改错1 Her name is Jack.( )2 I's Gina.( )3 Peter is his last name.( )二 用代词填空 1 - __name is Mary.___am a girl2 - __telephone number is 295 - 81463 ... - 作业帮
充芝17517178700…… [答案] 1 her改his 2 I's改I'm 3 改 Peter is his firt name 二 1 her I 2 My 3 his(her) 4 His,his

@邱有4885:一般将来时 1.主语+will+动词原形 2.主语+be(is/am/are)+going to+动词原形 1.主语+will+动词原形陈述句:Lily will visit her uncle in Beijing next month.否定句:... - 作业帮
充芝17517178700…… [答案] 1.主语+will+动词原形 陈述句:Lily will visit her uncle in Beijing next month. 否定句:Lily won't visit her uncle in Beijing next month. 一般疑问句:Will Lily visit her uncle in Beijing next month? 肯定回答句:Yes,she will 否定回答句:No,she won't 特殊疑...

@邱有4885:her name is rose改为一般疑问句+肯定回答+否定回答 - 作业帮
充芝17517178700…… [答案] Is her name Rose? Yes,it is. No,it isn't.

@邱有4885:1. - - is a nem student.--name is Bob.(he) 2.--am Tony.--come from China.(l) -
充芝17517178700…… 你好1. He his2. I I3. you4. her5. She ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ 祝你学习进步,更上一层楼!不明白请及时追问,满意敬请采纳,O(∩_∩)O谢谢~~

@邱有4885:设A,B,C均为n阶方阵,E为n阶单位阵,若B=E+AB,C=A+CA,则B - C= -
充芝17517178700…… 设A,B,C均为n阶方阵,E为n阶单位阵, 则由于B=E+AB,则(E-A) B=E,则E-A和B均可逆,且B=(E-A)^-1 又因为C=A+CA,则C(E-A)=A,C=A(E-A)^-1 所以B-C=((E-A)^-1)-(A(E-A)^-1)=(E-A)((E-A)^-1)=E

@邱有4885: 阅读理解      Hi! My name is Tina. I' m an English girl. I like sports and my favorite (最喜欢的) sport is ping - pong. My Favorite ping - pong star is a ... - 作业帮
充芝17517178700…… [答案] 1-5 CABCB

@邱有4885:已知abc=1,求a/ab+a+1 +b/bc+b+1 +c/ca+c+1的值 -
充芝17517178700…… 已知abc=1 a/(ab+a+1) +b/(bc+b+1) +c/(ca+c+1)=a/(ab+a+1)+ab/(abc+ab+a) +abc/(abca+abc+ab)=a/(ab+a+1)+ab/(1+ab+a) +1/(a+1+ab)=(a+ab+1)/(a+ab+1)=1

@邱有4885:若abc=1,求证:(1/ab+a+1)+(1/bc+b+1)+(1/ca+c+1)=1. -
充芝17517178700…… 证明: 因为abc=1,所以1/ab+a+1=abc/ab+a+abc=bc/b+1+bc 1/ca+c+1=abc/ca+c+abc=ab/a+1+ab=ab/a+abc+ab=b/1+bc+b 所以 (1/ab+a+1)+(1/bc+b+1)+(1/ca+c+1)=(bc/b+1+bc)+(1/bc+b+1)+(b/1+bc+b)=1

@邱有4885:已知|a|/a+|b|/b+|c|/c= - 1,求ab/|ab|+bc/|bc|+ca/|ca|+abc/|abc|的值 (注:| |为绝对值) -
充芝17517178700…… 两个负数; 而abc是正数. 于是已知|a|/a+|b|/b+|c|/c=-1, a: ab/|ab|+bc/|bc|+ca/|ca|+abc/,c三个数中一定有一个正数,两个负数,bc,ca三个数中也一定有一个正数; 则ab,b,则可见

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