i+b+works官网
@姚泻1053：1.few +名词的单数还是复数2.I have read ( ) of the young writer.A,works B,work,C,an works D.the works3.when we saw his face ,we knew ( )was bad ,A.some ... - 作业帮
蔚重19160419442…… [答案] 1. few修饰可数 few用于肯定句 a few用于否定句 little修饰不可属 little用于肯定句 a little用于否定句
@姚泻1053：若(a+2i)i=b+i,其中a,b∈R,i是虚数单位,则a - b=( )A. - 3B. - 2C.2D.3 - 作业帮
蔚重19160419442…… [答案] ∵(a+2i)i=b+i,∴-2+ai=b+i,∴b=-2、a=1,∴a-b=3, 故选:D.
@姚泻1053：若复数z满足1 - z÷1+z=i,则丨1+z丨= A.0 B.1 C.根号2 D.2 - 作业帮
蔚重19160419442…… [答案] 设z=a+bi (a、b为实数,且b≠0)(1-z)/(1+z)=i1-z=(1+z)i1-a-bi=(1+a+bi)i整理,得(a-b-1)+(a+b+1)i=0a-b-1=0a+b+1=0解得a=0 b=-1z=-i z+1=1-i|z+1|=√[1²+(-1)²]=√2|z+1|的值为√2.
@姚泻1053：若(a+2i)i=b+i,其中a、b∈R,i是虚数单位,则a+b=( )A. - 1B.1C. - 3D.3 - 作业帮
蔚重19160419442…… [答案] 因为(a+2i)i=-2+ai=b+i 所以 a=1b=−2 所以a+b=-1. 故选A
@姚泻1053：写出句式:主语+谓语(系动词)+as+形容词或副词+as+从句 -
蔚重19160419442…… 1.主语+谓语(实意动词)+as+副词+as+从句 He works as hard as I (do). 这里用do代替前面的 work,避免重复,且通常省略. 2.主语+谓语(系动词)+as+形容词+as+从句 She is as tall as his mother (is) 后面的is通常省略. 元音在弱读音节中的元音单词,away,understand,conversation r组合的元音单词,teacher,doctor,regard,nurse,
@姚泻1053：已知Ia - b+2I+Ib+3I互为相反数,求a与b的值 - 作业帮
蔚重19160419442…… [答案] 知Ia-b+2I+Ib+3I互为相反数,求a与b的值 a-b+2 = 0 b+3 = 0 b= -3 a = b-2 = -3-2 = -5
@姚泻1053：若I a I =5 I b I=2 则a+b的值为( ) - 作业帮
蔚重19160419442…… [选项] A. ±3 B. ±7 C. 3或7 D. ±3或±7
@姚泻1053：i had a few - _ - to do in the town this morning.a.works b.jobs说明下, - 作业帮
蔚重19160419442…… [答案] 选B, work 不可数名词,后面不加s,如I have a lot of work to do. job 是可数名词. a few 修饰可数名词.
@姚泻1053：请问 零序电流过滤器到底是一次电流和等于3I0=IA+IB+IC还是二次电流和等于3I0=Ia+Ib+Ic呢?书上怎么写的都有啊.电压互感器也是一样的,到底是一次电压... - 作业帮
蔚重19160419442…… [答案] 零序电流说的都是一次的,只不过通过零序电流互感器采集到的,
@姚泻1053：已知Ia+1I与Ib+2I互为相反数详细说明原因 - 作业帮
蔚重19160419442…… [答案] 已知Ia+1I与Ib+2I互为相反数 而且二者都是大于大于零 所以只有二者都等于零,才会是相反数 所以Ia+1I=0 Ib+2I=0 解得a=-1 b=-2
蔚重19160419442…… [答案] 1. few修饰可数 few用于肯定句 a few用于否定句 little修饰不可属 little用于肯定句 a little用于否定句
@姚泻1053：若(a+2i)i=b+i,其中a,b∈R,i是虚数单位,则a - b=( )A. - 3B. - 2C.2D.3 - 作业帮
蔚重19160419442…… [答案] ∵(a+2i)i=b+i,∴-2+ai=b+i,∴b=-2、a=1,∴a-b=3, 故选:D.
@姚泻1053：若复数z满足1 - z÷1+z=i,则丨1+z丨= A.0 B.1 C.根号2 D.2 - 作业帮
蔚重19160419442…… [答案] 设z=a+bi (a、b为实数,且b≠0)(1-z)/(1+z)=i1-z=(1+z)i1-a-bi=(1+a+bi)i整理,得(a-b-1)+(a+b+1)i=0a-b-1=0a+b+1=0解得a=0 b=-1z=-i z+1=1-i|z+1|=√[1²+(-1)²]=√2|z+1|的值为√2.
@姚泻1053：若(a+2i)i=b+i,其中a、b∈R,i是虚数单位,则a+b=( )A. - 1B.1C. - 3D.3 - 作业帮
蔚重19160419442…… [答案] 因为(a+2i)i=-2+ai=b+i 所以 a=1b=−2 所以a+b=-1. 故选A
@姚泻1053：写出句式:主语+谓语(系动词)+as+形容词或副词+as+从句 -
蔚重19160419442…… 1.主语+谓语(实意动词)+as+副词+as+从句 He works as hard as I (do). 这里用do代替前面的 work,避免重复,且通常省略. 2.主语+谓语(系动词)+as+形容词+as+从句 She is as tall as his mother (is) 后面的is通常省略. 元音在弱读音节中的元音单词,away,understand,conversation r组合的元音单词,teacher,doctor,regard,nurse,
@姚泻1053：已知Ia - b+2I+Ib+3I互为相反数,求a与b的值 - 作业帮
蔚重19160419442…… [答案] 知Ia-b+2I+Ib+3I互为相反数,求a与b的值 a-b+2 = 0 b+3 = 0 b= -3 a = b-2 = -3-2 = -5
@姚泻1053：若I a I =5 I b I=2 则a+b的值为( ) - 作业帮
蔚重19160419442…… [选项] A. ±3 B. ±7 C. 3或7 D. ±3或±7
@姚泻1053：i had a few - _ - to do in the town this morning.a.works b.jobs说明下, - 作业帮
蔚重19160419442…… [答案] 选B, work 不可数名词,后面不加s,如I have a lot of work to do. job 是可数名词. a few 修饰可数名词.
@姚泻1053：请问 零序电流过滤器到底是一次电流和等于3I0=IA+IB+IC还是二次电流和等于3I0=Ia+Ib+Ic呢?书上怎么写的都有啊.电压互感器也是一样的,到底是一次电压... - 作业帮
蔚重19160419442…… [答案] 零序电流说的都是一次的,只不过通过零序电流互感器采集到的,
@姚泻1053：已知Ia+1I与Ib+2I互为相反数详细说明原因 - 作业帮
蔚重19160419442…… [答案] 已知Ia+1I与Ib+2I互为相反数 而且二者都是大于大于零 所以只有二者都等于零,才会是相反数 所以Ia+1I=0 Ib+2I=0 解得a=-1 b=-2
