python判断闰年最简单
@史祥2161：用python编写程序判断闰年? -
终亲17582436152…… # Leap Year Check if year % 4 == 0 and year % 100 != 0: print(year, ＂是闰年＂) elif year % 100 == 0: print(year, ＂不是闰年＂) elif year % 400 ==0: print(year, ＂是闰年＂) else: print(year, ＂不是闰年＂)
@史祥2161：利用python算闰年 -
终亲17582436152…… start = int(raw_input('Starting year : ')); stop = int(raw_input('Ending year : ')); leap = 0; for year in range(start, stop+1) : if (year%4 == 0 and (year%100 != 0 or year%400 == 0) ) : print year, ＂is leap year＂; leap += 1; else : print year, ＂is not a leap year＂ print ＂Total number of leap years : ＂, leap
@史祥2161：Python判断闰年与否 -
终亲17582436152…… def leap(year): if year % 400 == 0: return True else: if year % 100 == 0: return False else: if year % 4 == 0: return True else: return False
@史祥2161：谁能用python做一个判断2000是不是闰年的编写,感激不尽,能做的直接做给我吧谢谢 -
终亲17582436152…… 闰年就是 能被4整除但不能被100整除,或能被400整除的年份. year = 2000 if (year % 4 == 0 and year % 100 != 0) or year % 400 == 0: print(year, '是闰年') else: print(year, '不是闰年')运行输出:
@史祥2161：python编程. 编写函数,输入年、月、日,计算该日是该年的第几天(注意判断该年是否为闰年).跪 -
终亲17582436152…… 1 2 3 4 !/usr/bin/python importdatetime dt =datetime.datetime(2012, 3, 16) print'%s'%dt.strftime('%j') 简单写写,自己添加吧
@史祥2161：用python计算2001 - 2050中的闰年 -
终亲17582436152…… [i for i in range(2001, 2051) if i%4 == 0 and (i%100 != 0 or i%400 == 0)]
@史祥2161：我用python 写了一个判断闰年的代码,想建立一个循环,但是总是无限循环或者没有答案 -
终亲17582436152…… def is_leap(year): year = int(year) return year % 400 == 0 or (year%4==0 and year%100!=0) for i in range(5): temp = input('输入你想要的年份') while not temp.isdigit(): temp = input(＂请输入整数＂) if is_leap(temp): print(temp+'是闰年') else: print(temp+'不是闰年')
@史祥2161：编写函数 以数组作为输入参数 判断一个年份是否为闰年;输入的是年份,急求啊!谢谢啦 -
终亲17582436152…… 知道闰年的算法就可以了.(year%4==0 and year%100!=0) or year%400==0#python def leap(years): for year in years: if (year%4==0 and year%100!=0) or year%400==0: print '%d is Leap Year' %year else: print '%d is not Leap Year'%year
@史祥2161：编写程序,根据给定的年分与月份,判断该年是否闰年 -
终亲17582436152…… #includebool IsLeap(int year){ return ( year % 400 == 0 || (year % 4 == 0 && year % 100 != 0) ); } void season(int month){ switch (month ) { case 3: case 4: case 5: printf(＂春季＂); break; case 6: case 7: case 8: printf(＂夏季＂); break; case ...
终亲17582436152…… # Leap Year Check if year % 4 == 0 and year % 100 != 0: print(year, ＂是闰年＂) elif year % 100 == 0: print(year, ＂不是闰年＂) elif year % 400 ==0: print(year, ＂是闰年＂) else: print(year, ＂不是闰年＂)
@史祥2161：利用python算闰年 -
终亲17582436152…… start = int(raw_input('Starting year : ')); stop = int(raw_input('Ending year : ')); leap = 0; for year in range(start, stop+1) : if (year%4 == 0 and (year%100 != 0 or year%400 == 0) ) : print year, ＂is leap year＂; leap += 1; else : print year, ＂is not a leap year＂ print ＂Total number of leap years : ＂, leap
@史祥2161：Python判断闰年与否 -
终亲17582436152…… def leap(year): if year % 400 == 0: return True else: if year % 100 == 0: return False else: if year % 4 == 0: return True else: return False
@史祥2161：谁能用python做一个判断2000是不是闰年的编写,感激不尽,能做的直接做给我吧谢谢 -
终亲17582436152…… 闰年就是 能被4整除但不能被100整除,或能被400整除的年份. year = 2000 if (year % 4 == 0 and year % 100 != 0) or year % 400 == 0: print(year, '是闰年') else: print(year, '不是闰年')运行输出:
@史祥2161：python编程. 编写函数,输入年、月、日,计算该日是该年的第几天(注意判断该年是否为闰年).跪 -
终亲17582436152…… 1 2 3 4 !/usr/bin/python importdatetime dt =datetime.datetime(2012, 3, 16) print'%s'%dt.strftime('%j') 简单写写,自己添加吧
@史祥2161：用python计算2001 - 2050中的闰年 -
终亲17582436152…… [i for i in range(2001, 2051) if i%4 == 0 and (i%100 != 0 or i%400 == 0)]
@史祥2161：我用python 写了一个判断闰年的代码,想建立一个循环,但是总是无限循环或者没有答案 -
终亲17582436152…… def is_leap(year): year = int(year) return year % 400 == 0 or (year%4==0 and year%100!=0) for i in range(5): temp = input('输入你想要的年份') while not temp.isdigit(): temp = input(＂请输入整数＂) if is_leap(temp): print(temp+'是闰年') else: print(temp+'不是闰年')
@史祥2161：编写函数 以数组作为输入参数 判断一个年份是否为闰年;输入的是年份,急求啊!谢谢啦 -
终亲17582436152…… 知道闰年的算法就可以了.(year%4==0 and year%100!=0) or year%400==0#python def leap(years): for year in years: if (year%4==0 and year%100!=0) or year%400==0: print '%d is Leap Year' %year else: print '%d is not Leap Year'%year
@史祥2161：编写程序,根据给定的年分与月份,判断该年是否闰年 -
终亲17582436152…… #includebool IsLeap(int year){ return ( year % 400 == 0 || (year % 4 == 0 && year % 100 != 0) ); } void season(int month){ switch (month ) { case 3: case 4: case 5: printf(＂春季＂); break; case 6: case 7: case 8: printf(＂夏季＂); break; case ...
