python判断闰年程序if函数
@闾廖4595：用python编写程序判断闰年? -
俟威13284858242…… # Leap Year Check if year % 4 == 0 and year % 100 != 0: print(year, ＂是闰年＂) elif year % 100 == 0: print(year, ＂不是闰年＂) elif year % 400 ==0: print(year, ＂是闰年＂) else: print(year, ＂不是闰年＂)
@闾廖4595：利用python算闰年 -
俟威13284858242…… start = int(raw_input('Starting year : ')); stop = int(raw_input('Ending year : ')); leap = 0; for year in range(start, stop+1) : if (year%4 == 0 and (year%100 != 0 or year%400 == 0) ) : print year, ＂is leap year＂; leap += 1; else : print year, ＂is not a leap year＂ print ＂Total number of leap years : ＂, leap
@闾廖4595：Python判断闰年与否 -
俟威13284858242…… def leap(year): if year % 400 == 0: return True else: if year % 100 == 0: return False else: if year % 4 == 0: return True else: return False
@闾廖4595：我用python 写了一个判断闰年的代码,想建立一个循环,但是总是无限循环或者没有答案 -
俟威13284858242…… def is_leap(year): year = int(year) return year % 400 == 0 or (year%4==0 and year%100!=0) for i in range(5): temp = input('输入你想要的年份') while not temp.isdigit(): temp = input(＂请输入整数＂) if is_leap(temp): print(temp+'是闰年') else: print(temp+'不是闰年')
@闾廖4595：用python计算2001 - 2050中的闰年 -
俟威13284858242…… [i for i in range(2001, 2051) if i%4 == 0 and (i%100 != 0 or i%400 == 0)]
@闾廖4595：用if函数判断当前年份为闰年 -
俟威13284858242…… 可以使用公式: =IF(DAY(＂3-1＂-1)=29,＂闰年＂,＂非闰年＂)
@闾廖4595：高中数学:闰年是指能被四整除且不能被一百整除,或者能被400整除的年份,编写一个程序,判断输入的年... -
俟威13284858242…… 用python def is_leap_year(year): if (year %4 == 0) and (year % 100 != 0 ): return True elif year % 400 == 0: return True else: return False
@闾廖4595：阿门~~~帮帮我吧~~~~判断闰年的代码是if (year % 4 == 0 && year % 100 != 0 || year % 400 == 0) -
俟威13284858242…… 判断是闰年 bool a = (year % 4 == 0 && year % 100 != 0) || year % 400 == 0 否定 bool b = !((year % 4 == 0 && year % 100 != 0) || year % 400 == 0)
@闾廖4595：写一程序,判断是否这一年闰年 -
俟威13284858242…… #include void main(){int year,a;printf(＂请输入年份:＂);scanf(＂%d＂,&year);if((year%4==0&&year%100!=0)||(year%400==0)) printf(＂\n%d此年是闰年\n＂,year);else printf(＂%d此年非闰年\n＂,year); }
@闾廖4595：输入一四位数判断是否为闰年的程序 -
俟威13284858242…… Function IsLeapYearA(ByVal yr As Integer) As Boolean If ((yr Mod 4) = 0) Then IsLeapYearA = ((yr Mod 100) > 0) Or ((yr Mod 400) = 0) End If
俟威13284858242…… # Leap Year Check if year % 4 == 0 and year % 100 != 0: print(year, ＂是闰年＂) elif year % 100 == 0: print(year, ＂不是闰年＂) elif year % 400 ==0: print(year, ＂是闰年＂) else: print(year, ＂不是闰年＂)
@闾廖4595：利用python算闰年 -
俟威13284858242…… start = int(raw_input('Starting year : ')); stop = int(raw_input('Ending year : ')); leap = 0; for year in range(start, stop+1) : if (year%4 == 0 and (year%100 != 0 or year%400 == 0) ) : print year, ＂is leap year＂; leap += 1; else : print year, ＂is not a leap year＂ print ＂Total number of leap years : ＂, leap
@闾廖4595：Python判断闰年与否 -
俟威13284858242…… def leap(year): if year % 400 == 0: return True else: if year % 100 == 0: return False else: if year % 4 == 0: return True else: return False
@闾廖4595：我用python 写了一个判断闰年的代码,想建立一个循环,但是总是无限循环或者没有答案 -
俟威13284858242…… def is_leap(year): year = int(year) return year % 400 == 0 or (year%4==0 and year%100!=0) for i in range(5): temp = input('输入你想要的年份') while not temp.isdigit(): temp = input(＂请输入整数＂) if is_leap(temp): print(temp+'是闰年') else: print(temp+'不是闰年')
@闾廖4595：用python计算2001 - 2050中的闰年 -
俟威13284858242…… [i for i in range(2001, 2051) if i%4 == 0 and (i%100 != 0 or i%400 == 0)]
@闾廖4595：用if函数判断当前年份为闰年 -
俟威13284858242…… 可以使用公式: =IF(DAY(＂3-1＂-1)=29,＂闰年＂,＂非闰年＂)
@闾廖4595：高中数学:闰年是指能被四整除且不能被一百整除,或者能被400整除的年份,编写一个程序,判断输入的年... -
俟威13284858242…… 用python def is_leap_year(year): if (year %4 == 0) and (year % 100 != 0 ): return True elif year % 400 == 0: return True else: return False
@闾廖4595：阿门~~~帮帮我吧~~~~判断闰年的代码是if (year % 4 == 0 && year % 100 != 0 || year % 400 == 0) -
俟威13284858242…… 判断是闰年 bool a = (year % 4 == 0 && year % 100 != 0) || year % 400 == 0 否定 bool b = !((year % 4 == 0 && year % 100 != 0) || year % 400 == 0)
@闾廖4595：写一程序,判断是否这一年闰年 -
俟威13284858242…… #include void main(){int year,a;printf(＂请输入年份:＂);scanf(＂%d＂,&year);if((year%4==0&&year%100!=0)||(year%400==0)) printf(＂\n%d此年是闰年\n＂,year);else printf(＂%d此年非闰年\n＂,year); }
@闾廖4595：输入一四位数判断是否为闰年的程序 -
俟威13284858242…… Function IsLeapYearA(ByVal yr As Integer) As Boolean If ((yr Mod 4) = 0) Then IsLeapYearA = ((yr Mod 100) > 0) Or ((yr Mod 400) = 0) End If
