python题目
@郭饱4827：python练习题1.The input is the numerator and denominator of the fraction.Somesample outputs of running the program are given below:Inpu t the numerator ... - 作业帮
门童17238365665…… [答案] def gcd(x, y): s = (x > y) and y or x while (x % s or y % s): s -= 1 return s def testfunc(n, d): g = gcd(n, d) n, d = n / g, d / g if n < d: return n, d if n % d: return n / d, n % d, d else: return n / d, def formater(*nums): fmt = [＂%d＂, ＂%d/%d＂, ＂%d %d/%d＂] ...
@郭饱4827：题目:有关Python语言的题,急!!!!!!
门童17238365665…… 晕....又碰到一个是这个做也的好友...给你贴下代码吧..哈哈 第一题: #!/usr/bin/env python#-*- coding: GB2312 -*- while True: filename = raw_input('输入文本路径:') if filename != 'exit': txtfile = file(filename, 'r+') content = txtfile.readlines() txtfile....
@郭饱4827：python 新手求指导习题.#根据给定的年月日以数字形式打印出日期months = ['January''February''March''April''May''June''July''August''September''October''... - 作业帮
门童17238365665…… [答案] 超出索引了,month_number-1 已经不在months这个list的索引范围了,3.3我没用过,但是看你的months写个估计有问题,难道3.3支持list里面不加逗号?估计你在每个月份后面加个逗号就好了……起码这里能过去,后面过不过得去...
@郭饱4827：一道python题 -
门童17238365665…… 按照题目要求编写的Python程序如下 n=1 i=1 m=1 print(＂{:>4s} {:>6s}＂.format(＂n＂,＂square＂)) while n<=25: print(＂{:>4d} {:>6d}＂.format(n,m)) i=i+2 m=m+i n=n+1 源代码(注意源代码的缩进)
@郭饱4827：python list中数字与一个数相乘比如说[1,2,3]与 2 相乘得[2,4,6] - 作业帮
门童17238365665…… [答案] a=[1,2,3] [x*2 for x in a] 结果[2,4,6]
@郭饱4827：python问题 m = [[1,2,3],[4,5,6],[7,8,9]] t = [r[1] for r in m] t [2,5,8] - 作业帮
门童17238365665…… [答案] m是由三个子列表[1,2,3],[4,5,6],[7,8,9]组成的,他们的下标为1的元素分别为2,5,8t = [r[1] for r in m]这是列表推导式,表示依次迭代m的一级子元素(列表),返回子列表中下标为1的子元素,组成一个新的列表[2,5,8]等价...
@郭饱4827：一道Python题,求高手解答 -
门童17238365665…… def operate(ASMD, num1, num2): if ASMD == 'A' or 'a': return num1 + num2 elif ASMD == 'S' or 's': return num1 - num2 elif ASMD == 'M' or 'm': return num1 * num2 elif ASMD == 'D' or 'D': return float(num1)/num2题目的意思应该是如上方法吧.num1,num2分别代表两个操作数,ASMD代表操作码.希望能帮到你
@郭饱4827：python问题:用二分法求根(递归)def root(x,p):low = 0hgh = xm = (low + high)/2if abs(m**2 - x) >> def f(m,x,low,high):if abs(m**2 - x) x:high = mm = (low + high)... - 作业帮
门童17238365665…… [答案] 拼写错误: hgh = x 改成high = x
@郭饱4827：python题目Write a function that computes and returns the sum of the digits in an integer. Use the following function header:def sum - digits(number):For example... - 作业帮
门童17238365665…… [答案] #!/usr/bin/env python#-*- coding:utf-8 -*-def sum_digits(number): ＂＂＂Return the sum of the number's digits＂...
@郭饱4827：Python简单的题目,大家都来做一下. -
门童17238365665…… 1 2 3 4 5 6 7 8 亲,你这2113个要直到满意为止5261,就明4102显不是简单的条件语句能完1653成专的,也不是简单的for循环能解决属的,肯定是while语句的啊... num =int(raw_input(＂Please input your number:＂)) whilenot0<num<101: print＂Please input a num between 1 and 100!＂ num =int(raw_input(＂Please input your number:＂)) else: printnum
门童17238365665…… [答案] def gcd(x, y): s = (x > y) and y or x while (x % s or y % s): s -= 1 return s def testfunc(n, d): g = gcd(n, d) n, d = n / g, d / g if n < d: return n, d if n % d: return n / d, n % d, d else: return n / d, def formater(*nums): fmt = [＂%d＂, ＂%d/%d＂, ＂%d %d/%d＂] ...
@郭饱4827：题目:有关Python语言的题,急!!!!!!
门童17238365665…… 晕....又碰到一个是这个做也的好友...给你贴下代码吧..哈哈 第一题: #!/usr/bin/env python#-*- coding: GB2312 -*- while True: filename = raw_input('输入文本路径:') if filename != 'exit': txtfile = file(filename, 'r+') content = txtfile.readlines() txtfile....
@郭饱4827：python 新手求指导习题.#根据给定的年月日以数字形式打印出日期months = ['January''February''March''April''May''June''July''August''September''October''... - 作业帮
门童17238365665…… [答案] 超出索引了,month_number-1 已经不在months这个list的索引范围了,3.3我没用过,但是看你的months写个估计有问题,难道3.3支持list里面不加逗号?估计你在每个月份后面加个逗号就好了……起码这里能过去,后面过不过得去...
@郭饱4827：一道python题 -
门童17238365665…… 按照题目要求编写的Python程序如下 n=1 i=1 m=1 print(＂{:>4s} {:>6s}＂.format(＂n＂,＂square＂)) while n<=25: print(＂{:>4d} {:>6d}＂.format(n,m)) i=i+2 m=m+i n=n+1 源代码(注意源代码的缩进)
@郭饱4827：python list中数字与一个数相乘比如说[1,2,3]与 2 相乘得[2,4,6] - 作业帮
门童17238365665…… [答案] a=[1,2,3] [x*2 for x in a] 结果[2,4,6]
@郭饱4827：python问题 m = [[1,2,3],[4,5,6],[7,8,9]] t = [r[1] for r in m] t [2,5,8] - 作业帮
门童17238365665…… [答案] m是由三个子列表[1,2,3],[4,5,6],[7,8,9]组成的,他们的下标为1的元素分别为2,5,8t = [r[1] for r in m]这是列表推导式,表示依次迭代m的一级子元素(列表),返回子列表中下标为1的子元素,组成一个新的列表[2,5,8]等价...
@郭饱4827：一道Python题,求高手解答 -
门童17238365665…… def operate(ASMD, num1, num2): if ASMD == 'A' or 'a': return num1 + num2 elif ASMD == 'S' or 's': return num1 - num2 elif ASMD == 'M' or 'm': return num1 * num2 elif ASMD == 'D' or 'D': return float(num1)/num2题目的意思应该是如上方法吧.num1,num2分别代表两个操作数,ASMD代表操作码.希望能帮到你
@郭饱4827：python问题:用二分法求根(递归)def root(x,p):low = 0hgh = xm = (low + high)/2if abs(m**2 - x) >> def f(m,x,low,high):if abs(m**2 - x) x:high = mm = (low + high)... - 作业帮
门童17238365665…… [答案] 拼写错误: hgh = x 改成high = x
@郭饱4827：python题目Write a function that computes and returns the sum of the digits in an integer. Use the following function header:def sum - digits(number):For example... - 作业帮
门童17238365665…… [答案] #!/usr/bin/env python#-*- coding:utf-8 -*-def sum_digits(number): ＂＂＂Return the sum of the number's digits＂...
@郭饱4827：Python简单的题目,大家都来做一下. -
门童17238365665…… 1 2 3 4 5 6 7 8 亲,你这2113个要直到满意为止5261,就明4102显不是简单的条件语句能完1653成专的,也不是简单的for循环能解决属的,肯定是while语句的啊... num =int(raw_input(＂Please input your number:＂)) whilenot0<num<101: print＂Please input a num between 1 and 100!＂ num =int(raw_input(＂Please input your number:＂)) else: printnum
