skylar+vox+shoplyfter

@瞿洪2234:明基投影机灯泡sho寿命3000h是什么意思 -
韦佳19125689993…… 投影机灯泡是一个高耗品,一般寿命在2500-5000个小时,你这个3000意思是从购买之日用起,差不多3000个小时后就要更换灯泡了,要不投影出来的东西就会偏灰,影响效果

@瞿洪2234:摩尔庄园摩尔们常用的英文名字 -
韦佳19125689993…… Suki Suki是可爱的,喜欢的意思. 这可以做英文名字,优琪. Sa'd Shirley Saad Shiva Saadiq Shivaji Saar Shlomo Saarik Shmuel Sabastian Sho Sabino Shobhan Sabir Shola Sabri Sholto Sacco Shomari Sacha Shon Sacharija Shone Sachdev ...

@瞿洪2234:My father is tall and has short gray hair. He wears glasses with heavy black frames(框). Here is a picture of him from 1968. What a surprise! In the picture, he's... - 作业帮
韦佳19125689993…… [答案] CBDC

@瞿洪2234:C语言文件读入读出问题 -
韦佳19125689993…… 写出没有问题.读入有问题.改为: #include "stdio.h" struct shohin_mast{ char s_code[5]; char s_name[30]; int s_tanka; int s_suryo; }; int main() { FILE *pf; pf=fopen("1.txt","rb"); //比如用rb表示读入二进制文件. struct shohin_mast ...

@瞿洪2234:用以下几个词填空 open move bother stand come listen seemfeel look 文章(pome):Someone - knocking at his door,door,door,But sho and what - where he's ... - 作业帮
韦佳19125689993…… [答案] Someone(is ) knocking at his door,door,door,But sho and what(look ) where he's not sure,sure sure He opens,he( listens ) ,he looks to left and right but nothing( seems ) to move in the pale moonlight ...

@瞿洪2234:正六棱锥底面周长为24,H为BC的中点,O为正六边形ABCDEF的中心,角SHO=60度1.棱锥的高2.斜高3.侧棱长 - 作业帮
韦佳19125689993…… [答案] 正六棱锥底面周长为24,所以边长为4,H为BC(边长)的中点,BH=CH=(1/2)BC=2 OH=CH*tan60=2√3 1.棱锥的高SO=OH*tan60=2√3*√3=6 2.斜高SH=OH*cos60=2√3*2=4√3 3.侧棱长=√[(HC)^2+(SH)^2]=√[(2^2+(4√3)^2=√(4+48)=...

@瞿洪2234:求哆啦A梦电影版的《人鱼大海战》片尾曲的音译~~ -
韦佳19125689993…… 音译我没有找到,这是罗马发音和日文中文歌词,希望能帮到你明日が来ちゃえば しばらく会えないけどa shi ta ga ki chi e ba shi ba ra ku a e na i ke do いつまでも...

@瞿洪2234:非谓语动词句型问题⒈ Children should be stopped from shoking(动词shoking为什么要加ing?)⒉It is kind of you to say so.(动词say前为什么要加to?) - 作业帮
韦佳19125689993…… [答案] stop from doing停止做某事 It is kind of you to do sth.你做某件事真好. 均为固定用法

@瞿洪2234:MATLAB求解Black - Sholes方程,假设:S=1;T=0.25;rf=0.1;K=1;如何用MATLAB求解方程中的VS*normcdf(d1) - K*exp( - rf*T)*normcdf(d2)=0.0294其中:d1=... - 作业帮
韦佳19125689993…… [答案] 貌似没有结果啊 clear syms V a S T K rf b; S=1;T=0.25;rf=0.1;K=1; a=log(S/(K*exp(-rf*T))); b=V*T; d1=(a+0.5*b)/sqrt(b); d2=(a+0.5*b)/sqrt(b)-sqrt(b); solve('S*normcdf(d1)-K*exp(-rf*T)*normcdf(d2)-0.0294=0',V)

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