while实现1-100求和
@谈裘2114：用c语言while语句实现1到100的累加和 -
钟侮19338828609…… #include<stdio.h> int main() { int i=1,sum=0;while(i++<=100) { sum+=i; } printf(＂sum=%d\n＂,sum); return 0; }
@谈裘2114：使用while循环语句求1到100的累加和 -
钟侮19338828609…… int n=0; int sum=0; while(n<=100) { n++; sum+=n; }
@谈裘2114：二、编程序,求1 - 100的和,编程输出求和结果(用while实现). -
钟侮19338828609…… #includ<stdio.h> main() { int x=1,p=0; while(x++<100) p+=x;printf(＂1+2+3+....+100=%d\n＂,p); }
@谈裘2114：求1到100的奇数之和及偶数之和,用while语句 -
钟侮19338828609…… # includevoid main() { int i=1; while(i<=100) { if(i%2==0) printf(＂%d ＂,i); i++; } }
@谈裘2114：c#do while语句实现1到100求和? -
钟侮19338828609…… using System; using System.Collections.Generic; using System.Linq; using System.Text; namespace ConsoleApplication3 { class Program { static void Main(string[] args) { int i = 1; int sum=0; do { sum=i+sum; i++; } while (i<=100); } } }
@谈裘2114：用while语句,求1到100的偶数之和 -
钟侮19338828609…… public class Demo05ShiCao{ public static void main(String[] args){ int sum1 = 0; for(int i = 1; i <= 100; i++){ if(i % 2 == 0){ sum1 +=i; } } System.out.println(＂结果是:＂ + sum1); System.out.println(＂====================================...
@谈裘2114：用while循环求1 - 100的和并输出结果 -
钟侮19338828609…… 好像没有写java的,我给补充下吧. public class He { public static viod main(String [] args) { int a = 1,b=0; while(a<=100) { b=a+b; a++; } System.out.println(＂1-100的合是:＂+b); } } 采纳哦
@谈裘2114：用while求1 - 100+奇数和,偶数积+++C语言
钟侮19338828609…… #include <stdio.h> #include <stdlib.h> //求1到100之间的奇数之和、偶数之积. int main() { int n = 1, sum = 0; double odd = 1; while (n <= 100) { if (n % 2 == 1) { sum += n; } else { odd *= n; } n++; } printf(＂sum=%d,odd=%d＂,sum,odd); system(＂pause＂); } 希望对你有所帮助,
@谈裘2114：一、C语言编程序,求1到100奇数和,编程输出求和结果.(用while..及for) -
钟侮19338828609…… main() { int i,sum=0; for(i=1;i<=100;i++) if(i%2==1) sum+=i; printf(＂%d\n＂,sum); i=1; sum=0; while(i<=100) { if(i%2==1) sum+=i; i++; } printf(＂%d\n＂,sum); }
@谈裘2114：mathematica 分别用Do 语句、For语句、While语句三种循环控制语句完成1到100所有自然数求和运算. - 作业帮
钟侮19338828609…… [答案] s = 0; Do[s += i,{i,100}]; s For[i = 0; s = 0,i
钟侮19338828609…… #include<stdio.h> int main() { int i=1,sum=0;while(i++<=100) { sum+=i; } printf(＂sum=%d\n＂,sum); return 0; }
@谈裘2114：使用while循环语句求1到100的累加和 -
钟侮19338828609…… int n=0; int sum=0; while(n<=100) { n++; sum+=n; }
@谈裘2114：二、编程序,求1 - 100的和,编程输出求和结果(用while实现). -
钟侮19338828609…… #includ<stdio.h> main() { int x=1,p=0; while(x++<100) p+=x;printf(＂1+2+3+....+100=%d\n＂,p); }
@谈裘2114：求1到100的奇数之和及偶数之和,用while语句 -
钟侮19338828609…… # includevoid main() { int i=1; while(i<=100) { if(i%2==0) printf(＂%d ＂,i); i++; } }
@谈裘2114：c#do while语句实现1到100求和? -
钟侮19338828609…… using System; using System.Collections.Generic; using System.Linq; using System.Text; namespace ConsoleApplication3 { class Program { static void Main(string[] args) { int i = 1; int sum=0; do { sum=i+sum; i++; } while (i<=100); } } }
@谈裘2114：用while语句,求1到100的偶数之和 -
钟侮19338828609…… public class Demo05ShiCao{ public static void main(String[] args){ int sum1 = 0; for(int i = 1; i <= 100; i++){ if(i % 2 == 0){ sum1 +=i; } } System.out.println(＂结果是:＂ + sum1); System.out.println(＂====================================...
@谈裘2114：用while循环求1 - 100的和并输出结果 -
钟侮19338828609…… 好像没有写java的,我给补充下吧. public class He { public static viod main(String [] args) { int a = 1,b=0; while(a<=100) { b=a+b; a++; } System.out.println(＂1-100的合是:＂+b); } } 采纳哦
@谈裘2114：用while求1 - 100+奇数和,偶数积+++C语言
钟侮19338828609…… #include <stdio.h> #include <stdlib.h> //求1到100之间的奇数之和、偶数之积. int main() { int n = 1, sum = 0; double odd = 1; while (n <= 100) { if (n % 2 == 1) { sum += n; } else { odd *= n; } n++; } printf(＂sum=%d,odd=%d＂,sum,odd); system(＂pause＂); } 希望对你有所帮助,
@谈裘2114：一、C语言编程序,求1到100奇数和,编程输出求和结果.(用while..及for) -
钟侮19338828609…… main() { int i,sum=0; for(i=1;i<=100;i++) if(i%2==1) sum+=i; printf(＂%d\n＂,sum); i=1; sum=0; while(i<=100) { if(i%2==1) sum+=i; i++; } printf(＂%d\n＂,sum); }
@谈裘2114：mathematica 分别用Do 语句、For语句、While语句三种循环控制语句完成1到100所有自然数求和运算. - 作业帮
钟侮19338828609…… [答案] s = 0; Do[s += i,{i,100}]; s For[i = 0; s = 0,i
