x加y爱的方程式电影
@子露4887:xy+2lnx=y^4,求dy -
杭钧19779706739…… xy+2lnx=y^4,求dy 两边同时对x求导: y+xy'+2/x=4y'y^3 所以y'=(y-2/x)/(4y^3-x)=(xy-2)/(4xy^3-x^2) 所以dy=【(xy-2)/(4xy^3-x^2)】dx
@子露4887:爱的方程式? -
杭钧19779706739…… 爱+爱=互相爱100%真爱=20%执着+10%想念+10%吃醋+10%疑心+20%甜蜜 +10%心疼+20%幸福
@子露4887:(1 - x^2)dy/dx+xy=1 -
杭钧19779706739…… 解:∵(1-x^2)dy/dx+xy=1 ==>(1-x^2)dy+xydx=dx ==>dy/(1-x^2)^(1/2)+xydx/(1-x^2)^(3/2)=dx/(1-x^2)^(3/2) (等式两端同除(1-x^2)^(3/2)) ==>dy/(1-x^2)^(1/2)+yd(1/(1-x^2)^(1/2))=dx/(1-x^2)^(3/2) ==>d(y/(1-x^2)^(1/2))=d(x/(1-x^2)^(1/2)) ==>y/(1-x^2)^(1/2)=x/(1-x^2)^(1/2)+C (C是常数) ==>y=x+C(1-x^2)^(1/2) ∴原方程的通解是y=x+C(1-x^2)^(1/2).
@子露4887:爱的方程式动态图是哪部电影 -
杭钧19779706739…… 韩国歌手K.Will的 MV《我 需要你》请速采纳啊 回答不易
@子露4887:微分方程(X +Y)dy + (Y +1)dx=0满足y(1)=2的特解 - 作业帮
杭钧19779706739…… [答案] (y+1)dx+(x+y)dy=0 d(y+1)/dy=1,d(x+y)/dx=1,恰当微分方程 ydx+dx+xdy+ydy=0 d(xy)+dx+d(y^2/2)=0 d(xy+x+y^2/2)=0 xy+x+y^2/2=C 2+1+2^2/2=C=5 xy+x+y^2/2=5
@子露4887:隐函数求导方程式e的y次方+xy - e=0两边对x求导得d(e的y次方+xy - e)/dx=e的y次方dy/dx+y+xdy/dx这一步看不明白, - 作业帮
杭钧19779706739…… [答案] e^y+xy-e=0两边对x求导∵y是x的函数∴e^y对x求导由链式法则知d(e^y)/dx=[d(e^y)/dy]*(dy/dx)=(e^y)(dy/dx)而xy对x求导由乘法公式知d(xy)/dx=x(dy/dx)+y(dx/dx)=x(dy/dx)+ye是常数,对x求导为0∴d(e^y+xy-e)/dx=d(e^y)...
杭钧19779706739…… xy+2lnx=y^4,求dy 两边同时对x求导: y+xy'+2/x=4y'y^3 所以y'=(y-2/x)/(4y^3-x)=(xy-2)/(4xy^3-x^2) 所以dy=【(xy-2)/(4xy^3-x^2)】dx
@子露4887:爱的方程式? -
杭钧19779706739…… 爱+爱=互相爱100%真爱=20%执着+10%想念+10%吃醋+10%疑心+20%甜蜜 +10%心疼+20%幸福
@子露4887:(1 - x^2)dy/dx+xy=1 -
杭钧19779706739…… 解:∵(1-x^2)dy/dx+xy=1 ==>(1-x^2)dy+xydx=dx ==>dy/(1-x^2)^(1/2)+xydx/(1-x^2)^(3/2)=dx/(1-x^2)^(3/2) (等式两端同除(1-x^2)^(3/2)) ==>dy/(1-x^2)^(1/2)+yd(1/(1-x^2)^(1/2))=dx/(1-x^2)^(3/2) ==>d(y/(1-x^2)^(1/2))=d(x/(1-x^2)^(1/2)) ==>y/(1-x^2)^(1/2)=x/(1-x^2)^(1/2)+C (C是常数) ==>y=x+C(1-x^2)^(1/2) ∴原方程的通解是y=x+C(1-x^2)^(1/2).
@子露4887:爱的方程式动态图是哪部电影 -
杭钧19779706739…… 韩国歌手K.Will的 MV《我 需要你》请速采纳啊 回答不易
@子露4887:微分方程(X +Y)dy + (Y +1)dx=0满足y(1)=2的特解 - 作业帮
杭钧19779706739…… [答案] (y+1)dx+(x+y)dy=0 d(y+1)/dy=1,d(x+y)/dx=1,恰当微分方程 ydx+dx+xdy+ydy=0 d(xy)+dx+d(y^2/2)=0 d(xy+x+y^2/2)=0 xy+x+y^2/2=C 2+1+2^2/2=C=5 xy+x+y^2/2=5
@子露4887:隐函数求导方程式e的y次方+xy - e=0两边对x求导得d(e的y次方+xy - e)/dx=e的y次方dy/dx+y+xdy/dx这一步看不明白, - 作业帮
杭钧19779706739…… [答案] e^y+xy-e=0两边对x求导∵y是x的函数∴e^y对x求导由链式法则知d(e^y)/dx=[d(e^y)/dy]*(dy/dx)=(e^y)(dy/dx)而xy对x求导由乘法公式知d(xy)/dx=x(dy/dx)+y(dx/dx)=x(dy/dx)+ye是常数,对x求导为0∴d(e^y+xy-e)/dx=d(e^y)...