click+to+sign+up
@国叶1955：Click a Windows Live ID to sign in 这句话 什么意思 -
厉扶15285607880…… 点击一下窗口的有效的ID或身份证明的号码,然后进入
@国叶1955：Click a Windows Live ID to sign in 这句话 什么意思
厉扶15285607880…… 你在微软的网站上下东西吧! 这个Windows Live ID是微软的一个授权号! 有三种途径获得:1,上微软网站申请.2,正式得到授权用户3,在BAIDU中搜搜看有没有共享的!
@国叶1955：vb编程 计算f=1 - 1/(2*3)+1/(3*4) - 1/(4*5)+……+1/(19*20) -
厉扶15285607880…… 1、sign = -1 2、for i=2 to 19 3、sign = -sign 给分吧.. 运行结果是0.8875428
@国叶1955：ter是什么意思及反义词 -
厉扶15285607880…… ter adv. 三次; 三倍; 三重; [例句]Click the green arrow> with the+ sign to generate a new TER.点击带有加号的绿色箭头>以生成一个新的TER.没有反义词
@国叶1955：Click the SIGN UP button below to activate your new xLive account! 什么意思啊
厉扶15285607880…… 点击下面的SIGN UP键,以启动您最新的xLive账户.
@国叶1955：编程求f=1+1/(2*3)+1/(3*4)+……+1/(19*20)在窗体上输出结果 -
厉扶15285607880…… Private Sub Command1_Click() f = 1 For i = 2 To 19 f = f + 1 / (i * (i + 1)) Next i Print f End Sub
@国叶1955：vb编程计算1 1/2! - 1/3! 1/4! - 1/5!的值 -
厉扶15285607880…… Private Sub Command1_Click() Dim f As Double Dim i As Integer Dim sign As Integer f = 1 sign = 1 For i = 2 To 5 sign = -sign f = f + sign * 1 / fac(i) Next i Print ＂1+1/2!-1/3!+1/4!-1/5! =＂; f End Sub Function fac(n As Integer) As Long Dim i As Integer fac = 1 For i = 2 To n fac = fac * i Next End Function
@国叶1955：用VB编程求pi=4(1–1/3+1/5–1/7+1/9–1……) -
厉扶15285607880…… Private Sub Form_Click() Dim i As Long, f As Integer, pi As Single i = 1 f = 1 Do pi = pi + (1 / i) * f f = -f i = i + 2 Loop While 1 / i > 0.00001 MsgBox 4 * pi End Sub
@国叶1955：计算 S=1! - 2!+3! - 4!+5! - 6!+7!… - 10!的值.(需至少使用一个自定义函数) -
厉扶15285607880…… #include <stdio.h> long fact(int n) ////求阶乘 { if(n==1) return 1; return n*fact(n-1); } long sum(int n) //求和函数 { int sign; long S=0; for(sign=-1;n>0;n--) { S+=sign*fact(n); sign*=sign; } return S; } int main() { int n=10; printf(＂1!- 2!+3!-4!+5!-6!+7!…-10!的值是%d＂,sum(n)); getchar(); return 0; }
@国叶1955：1 - 2+3 - 4+5 - 6+···N 怎样编这个东西?
厉扶15285607880…… 1./*输出显示1-2+3-4+5-6+...n式子*/ #include void main() { int n; printf(＂please input N:＂); scanf(＂%d＂,&n); n++; for(int i=1;i void main() { int n,sum=0; printf(＂please input N:＂); scanf(＂%d＂,&n); n++; for(int i=1;i全部
厉扶15285607880…… 点击一下窗口的有效的ID或身份证明的号码,然后进入
@国叶1955：Click a Windows Live ID to sign in 这句话 什么意思
厉扶15285607880…… 你在微软的网站上下东西吧! 这个Windows Live ID是微软的一个授权号! 有三种途径获得:1,上微软网站申请.2,正式得到授权用户3,在BAIDU中搜搜看有没有共享的!
@国叶1955：vb编程 计算f=1 - 1/(2*3)+1/(3*4) - 1/(4*5)+……+1/(19*20) -
厉扶15285607880…… 1、sign = -1 2、for i=2 to 19 3、sign = -sign 给分吧.. 运行结果是0.8875428
@国叶1955：ter是什么意思及反义词 -
厉扶15285607880…… ter adv. 三次; 三倍; 三重; [例句]Click the green arrow> with the+ sign to generate a new TER.点击带有加号的绿色箭头>以生成一个新的TER.没有反义词
@国叶1955：Click the SIGN UP button below to activate your new xLive account! 什么意思啊
厉扶15285607880…… 点击下面的SIGN UP键,以启动您最新的xLive账户.
@国叶1955：编程求f=1+1/(2*3)+1/(3*4)+……+1/(19*20)在窗体上输出结果 -
厉扶15285607880…… Private Sub Command1_Click() f = 1 For i = 2 To 19 f = f + 1 / (i * (i + 1)) Next i Print f End Sub
@国叶1955：vb编程计算1 1/2! - 1/3! 1/4! - 1/5!的值 -
厉扶15285607880…… Private Sub Command1_Click() Dim f As Double Dim i As Integer Dim sign As Integer f = 1 sign = 1 For i = 2 To 5 sign = -sign f = f + sign * 1 / fac(i) Next i Print ＂1+1/2!-1/3!+1/4!-1/5! =＂; f End Sub Function fac(n As Integer) As Long Dim i As Integer fac = 1 For i = 2 To n fac = fac * i Next End Function
@国叶1955：用VB编程求pi=4(1–1/3+1/5–1/7+1/9–1……) -
厉扶15285607880…… Private Sub Form_Click() Dim i As Long, f As Integer, pi As Single i = 1 f = 1 Do pi = pi + (1 / i) * f f = -f i = i + 2 Loop While 1 / i > 0.00001 MsgBox 4 * pi End Sub
@国叶1955：计算 S=1! - 2!+3! - 4!+5! - 6!+7!… - 10!的值.(需至少使用一个自定义函数) -
厉扶15285607880…… #include <stdio.h> long fact(int n) ////求阶乘 { if(n==1) return 1; return n*fact(n-1); } long sum(int n) //求和函数 { int sign; long S=0; for(sign=-1;n>0;n--) { S+=sign*fact(n); sign*=sign; } return S; } int main() { int n=10; printf(＂1!- 2!+3!-4!+5!-6!+7!…-10!的值是%d＂,sum(n)); getchar(); return 0; }
@国叶1955：1 - 2+3 - 4+5 - 6+···N 怎样编这个东西?
厉扶15285607880…… 1./*输出显示1-2+3-4+5-6+...n式子*/ #include void main() { int n; printf(＂please input N:＂); scanf(＂%d＂,&n); n++; for(int i=1;i void main() { int n,sum=0; printf(＂please input N:＂); scanf(＂%d＂,&n); n++; for(int i=1;i全部
