sin2x除以cos2x化简
@邹先4022: 函数f(x)= sin2x - cos2x可化简为_________. - 作业帮
骆胁15749992714…… [答案] f(x)=2sin(2x-).
@邹先4022:函数f(x)=sin2x - cos2x可化简为_________________. - 作业帮
骆胁15749992714…… [答案] f(x)=2sin(2x-).
@邹先4022:sin2x - cos2x - 1 化简 - 作业帮
骆胁15749992714…… [答案] 原式=√2(√2/2*sin2x-√2/2cos2x)-1 =√2(sin2xcosπ/4-cos2xsinπ/4)-1 =√2sin(x-π/4)-1
@邹先4022:y=sin2x*cos2x怎么化简 -
骆胁15749992714…… y=(1/2)sin4x
@邹先4022:sin2x cos2x怎么化简 -
骆胁15749992714…… sin2x cos2x=(1/2)sin4x
@邹先4022:Sin2X - Cos2X化简后=多少?
骆胁15749992714…… 根号二倍Sin(2x-拍/4)
@邹先4022:1. 化简:sin2x+cos2x -
骆胁15749992714…… 1. sin2x+cos2x=根号2sin(2x+pi/4) 2. 函数y=cos(x-pai/8)x取2/3pai取最小值 y=cos(2/3pai-pai/8)=y=cos(13/24pai)=cos(1/2pqi-1/24pai)=sin(1/24pai)=sin(7.5度) 计算这个建议用计算机
@邹先4022:f(x)=sin2x*cos2x如何化简? 详细步骤 -
骆胁15749992714…… 解:∵f(x)=(cos2x sin2x)/(cos2x-sin2x) ∴f(x)=√2sin(2x π/4)/√2cos(2x π/4)=√2tan(2x π/4) ∴t=π/w=π/2 ∴最小正周期是π/2
@邹先4022:sin2x*cos2x/2,化简. - 作业帮
骆胁15749992714…… [答案] sin(2x)cos(2x)/2 =2sin(2x)cos(2x)/4 =sin(4x) /4 三角函数的化简就是降次的过程,本题中sin(2x)cos(2x),次数为2次,需要降次.
@邹先4022:化简:(1 - sin2x)∕(cos2x) - 作业帮
骆胁15749992714…… [答案] (1-sin2x)∕(cos2x) =(sin²x+cos²x-2sinxcosx)/(cos²x-sin²x) =(cosx-sinx)²/[(cosx-sinx)(cosx+sinx)] =(cosx-sinx)/(cosx+sinx) =(tanx-1)/(tanx+1)
骆胁15749992714…… [答案] f(x)=2sin(2x-).
@邹先4022:函数f(x)=sin2x - cos2x可化简为_________________. - 作业帮
骆胁15749992714…… [答案] f(x)=2sin(2x-).
@邹先4022:sin2x - cos2x - 1 化简 - 作业帮
骆胁15749992714…… [答案] 原式=√2(√2/2*sin2x-√2/2cos2x)-1 =√2(sin2xcosπ/4-cos2xsinπ/4)-1 =√2sin(x-π/4)-1
@邹先4022:y=sin2x*cos2x怎么化简 -
骆胁15749992714…… y=(1/2)sin4x
@邹先4022:sin2x cos2x怎么化简 -
骆胁15749992714…… sin2x cos2x=(1/2)sin4x
@邹先4022:Sin2X - Cos2X化简后=多少?
骆胁15749992714…… 根号二倍Sin(2x-拍/4)
@邹先4022:1. 化简:sin2x+cos2x -
骆胁15749992714…… 1. sin2x+cos2x=根号2sin(2x+pi/4) 2. 函数y=cos(x-pai/8)x取2/3pai取最小值 y=cos(2/3pai-pai/8)=y=cos(13/24pai)=cos(1/2pqi-1/24pai)=sin(1/24pai)=sin(7.5度) 计算这个建议用计算机
@邹先4022:f(x)=sin2x*cos2x如何化简? 详细步骤 -
骆胁15749992714…… 解:∵f(x)=(cos2x sin2x)/(cos2x-sin2x) ∴f(x)=√2sin(2x π/4)/√2cos(2x π/4)=√2tan(2x π/4) ∴t=π/w=π/2 ∴最小正周期是π/2
@邹先4022:sin2x*cos2x/2,化简. - 作业帮
骆胁15749992714…… [答案] sin(2x)cos(2x)/2 =2sin(2x)cos(2x)/4 =sin(4x) /4 三角函数的化简就是降次的过程,本题中sin(2x)cos(2x),次数为2次,需要降次.
@邹先4022:化简:(1 - sin2x)∕(cos2x) - 作业帮
骆胁15749992714…… [答案] (1-sin2x)∕(cos2x) =(sin²x+cos²x-2sinxcosx)/(cos²x-sin²x) =(cosx-sinx)²/[(cosx-sinx)(cosx+sinx)] =(cosx-sinx)/(cosx+sinx) =(tanx-1)/(tanx+1)