tan+a+b+公式推导
@尚佳2299:tan(A+B)=(tanA+tanB)/(1 - tanAtanB) 推导过程 -
路狱15890306253…… tan(A+B) =sin(A+B)/cos(A+B) =(sinAcosB+sinBcosA)/(cosAcosB-sinAsinB) 分子,分母同时除以cosAcosB得: =(sinA/cosA+sinB/cosB)/(1-sinAsinB/cosAcosB) =(tanA+tanB)/(1-tanAtanB)
@尚佳2299:跪求tan(A+B)的公式 -
路狱15890306253…… (tanA+tanB)/1-tanAtanB
@尚佳2299:tan(a+b)=??公式
路狱15890306253…… tan(A+B)=tanA+tanB/1-tanA*tanB tan(A-B)=tanA-tanB/1+tanA*tanB
@尚佳2299:三角函数tan(a+b)=tana+tanb/1 - tana*tanb的推导过程!能说下tan(a+b)怎么推导成tana+tanb/1 - tana*tanb这步的全过程吗?越详细越好大哥大姐考你们啦! - 作业帮
路狱15890306253…… [答案] tan(A+B)=sin(A+B)/cos(A+B)=(sinAcosB+sinBcosA)/(cosAcosB-sinAsinB)分子,分母同时除以cosAcosB得:=(sinA/cosA+sinB/cosB)/(1-sinAsinB/cosAcosB)=(tanA+tanB)/(1-tanAtanB)
@尚佳2299:tan(a+b)等于什么 推导过程 -
路狱15890306253…… tanα·cotα=1 sinα·cscα=1 cosα·secα=1 sinα/cosα=tanα=secα/cscα cosα/sinα=cotα=cscα/secα sin2α+cos2α=1 1+tan2α=sec2α 1+cot2α=csc2α诱导公式sin(-α)=-sinα cos(-α)=cosαtan(-α)=-tanα cot(-α)=-cotαsin(π/2-α)=cosα cos(π/2-α)=sinα tan(π/2-α...
@尚佳2299:tan(a+b)= 公式.. -
路狱15890306253…… (tan a +tan b)/(1-tan a *tan b)
@尚佳2299:tan(a+b)=? -
路狱15890306253…… sin(A+B) = sinAcosB+cosAsinB cos(A+B) = cosAcosB-sinAsinB tan(A+B) = (tanA+tanB)/(1-tanAtanB) cot(A+B) = (cotAcotB-1)/(cotB+cotA)
@尚佳2299:求公式tan(a+b)=(tana+tanb)/(1 - tanatanb)的证明 - 作业帮
路狱15890306253…… [答案] tanA+tanB =sinA/cosA+sinB/cosB=(sinAcosB+cosAsinB)/(cosAcosB) =sin(A+B)/(cosAcosB)=[sin(A+B)/cos(A+B)][cos(A+B)/(cosAcosB)] =tan(A+B)[(cosAcosB-sinAsinB)/(cosAcosB)] =tan(A+B)[1-(sinA/cosA)(sinB/cosB)] =tan(A+B)(1-tanAtanB)
@尚佳2299:tan(A+B)=tanA+tanB+tanAtanB?? -
路狱15890306253…… 不相等,正确的式子应该是tan(A+B)=tanA+tanB+tanAtanBtan(A+B) 推倒的方式如下:∵tan(A+B)=(tanA+tanB)/(1- tanAtanB) tanA+tanB=(1- tanAtanB)(tan(A+B)) ∴tanA+tanB+tanAtanBtan(A+B) =(1- tanAtanB)tan(A+B)+tanAtanBtan(A+B) =tan(A+B)(1-tanAtanB+tanAtanB) =tan(A+B)
@尚佳2299:三角的和差公式 tan(a+b)=? tan(a - b)=? -
路狱15890306253…… tan(a+b)=(tana+tanb)/(1-tana tanb)tan(a-b)=(tana-tanb)/(1+tana tanb) 【问题补充:tan(π-α)= -tanαtan2α = 2tanα/(1-tan^2α)tana*tanb = (tana+tanb)/(cota+cotb) = - (tana-tanb)/(cota+cotb)
路狱15890306253…… tan(A+B) =sin(A+B)/cos(A+B) =(sinAcosB+sinBcosA)/(cosAcosB-sinAsinB) 分子,分母同时除以cosAcosB得: =(sinA/cosA+sinB/cosB)/(1-sinAsinB/cosAcosB) =(tanA+tanB)/(1-tanAtanB)
@尚佳2299:跪求tan(A+B)的公式 -
路狱15890306253…… (tanA+tanB)/1-tanAtanB
@尚佳2299:tan(a+b)=??公式
路狱15890306253…… tan(A+B)=tanA+tanB/1-tanA*tanB tan(A-B)=tanA-tanB/1+tanA*tanB
@尚佳2299:三角函数tan(a+b)=tana+tanb/1 - tana*tanb的推导过程!能说下tan(a+b)怎么推导成tana+tanb/1 - tana*tanb这步的全过程吗?越详细越好大哥大姐考你们啦! - 作业帮
路狱15890306253…… [答案] tan(A+B)=sin(A+B)/cos(A+B)=(sinAcosB+sinBcosA)/(cosAcosB-sinAsinB)分子,分母同时除以cosAcosB得:=(sinA/cosA+sinB/cosB)/(1-sinAsinB/cosAcosB)=(tanA+tanB)/(1-tanAtanB)
@尚佳2299:tan(a+b)等于什么 推导过程 -
路狱15890306253…… tanα·cotα=1 sinα·cscα=1 cosα·secα=1 sinα/cosα=tanα=secα/cscα cosα/sinα=cotα=cscα/secα sin2α+cos2α=1 1+tan2α=sec2α 1+cot2α=csc2α诱导公式sin(-α)=-sinα cos(-α)=cosαtan(-α)=-tanα cot(-α)=-cotαsin(π/2-α)=cosα cos(π/2-α)=sinα tan(π/2-α...
@尚佳2299:tan(a+b)= 公式.. -
路狱15890306253…… (tan a +tan b)/(1-tan a *tan b)
@尚佳2299:tan(a+b)=? -
路狱15890306253…… sin(A+B) = sinAcosB+cosAsinB cos(A+B) = cosAcosB-sinAsinB tan(A+B) = (tanA+tanB)/(1-tanAtanB) cot(A+B) = (cotAcotB-1)/(cotB+cotA)
@尚佳2299:求公式tan(a+b)=(tana+tanb)/(1 - tanatanb)的证明 - 作业帮
路狱15890306253…… [答案] tanA+tanB =sinA/cosA+sinB/cosB=(sinAcosB+cosAsinB)/(cosAcosB) =sin(A+B)/(cosAcosB)=[sin(A+B)/cos(A+B)][cos(A+B)/(cosAcosB)] =tan(A+B)[(cosAcosB-sinAsinB)/(cosAcosB)] =tan(A+B)[1-(sinA/cosA)(sinB/cosB)] =tan(A+B)(1-tanAtanB)
@尚佳2299:tan(A+B)=tanA+tanB+tanAtanB?? -
路狱15890306253…… 不相等,正确的式子应该是tan(A+B)=tanA+tanB+tanAtanBtan(A+B) 推倒的方式如下:∵tan(A+B)=(tanA+tanB)/(1- tanAtanB) tanA+tanB=(1- tanAtanB)(tan(A+B)) ∴tanA+tanB+tanAtanBtan(A+B) =(1- tanAtanB)tan(A+B)+tanAtanBtan(A+B) =tan(A+B)(1-tanAtanB+tanAtanB) =tan(A+B)
@尚佳2299:三角的和差公式 tan(a+b)=? tan(a - b)=? -
路狱15890306253…… tan(a+b)=(tana+tanb)/(1-tana tanb)tan(a-b)=(tana-tanb)/(1+tana tanb) 【问题补充:tan(π-α)= -tanαtan2α = 2tanα/(1-tan^2α)tana*tanb = (tana+tanb)/(cota+cotb) = - (tana-tanb)/(cota+cotb)