to+solve+a+problem

@伏胥1302:It is more difficult to solve a problem than that of finding a question. 详细句子结构分析 -
郗泻19785593444…… 句意:比起找出一个问题来,解决一个难题更难.分析:句型:It's + 形容词 + to do . 意为做某事如何.it 是形式主语,形容词做表语,不定式to do是真正的主语.后面的than…question这个短语做状语.that是表示比较的对象,of finding a question说明that的内容.

@伏胥1302:to solve the problem是什么意思 -
郗泻19785593444…… to solve the problem 解决问题 双语对照 词典结果:网络释义1. 解决问题 例句:1.Baa wants to solve the problem by building a third runway at heathrow. baa想通过建设西斯罗第三条飞机跑道解决这个问题.----------------------------------- 如有疑问欢迎追问!满意请点击右上方【选为满意回答】按钮

@伏胥1302:The ability to solve problems is not easy for children to learnThe ability 作主语 to solve problems 作The ability 的定语is(not) 系动词+easy 表语=谓语For 介词+... - 作业帮
郗泻19785593444…… [答案] 可以这么理解.

@伏胥1302:the problem was too tough to() A be solved B solve C solving D solve it 选哪个请解释 -
郗泻19785593444…… 选B:这里是不定式的主动表被动,请记住在表示某物或某事的特性的时候通常用主动表被动.举几个例子:1,The pen is easy to write.2`I don't have a friend to play with. 实在弄不清楚只有记住;the problem was too tough to solve. 这样看:成solve the problem.也就是说solve后面的宾语在前面,这样就不缺了.

@伏胥1302:MATLAB中solve如何去掉中间变量 -
郗泻19785593444…… 给你一个例子吧.solve('a*x=1','a') solve('a*x=1','x') 即后面的是要求的表达式.你的式子比较复杂,我就不知道能不能得到答案.方程组可以参考:[xx,yy]=solve('a*x+b*y-c=0','e*x+f*y-g=0','x','y') 不过你的问题有点怪怪的.x是变量,四个方程应当只能消掉三个中间变量.

@伏胥1302:matlab 中solve循环比如: i=1:10 s=solve('x^3+x^2+x=1=i','x') -
郗泻19785593444…… n = 10; i = 1:n; s = cell(1,n); for i = 1:n ep = ['solve(''x^3+x^2+x =' num2str(i) ''')']; s{i} = eval(ep); end; vpa(s{1},4) ans = 0.5437 - 0.7718 + 1.115*i - 0.7718 - 1.115*i vpa(s{2},4) ans = 0.8105 - 0.9053 + 1.284*i - 0.9053 - 1.284*i vpa(s{3},4) ans = 1.0 - 1.0 + 1.414*i - 1.0 - 1.414*i

@伏胥1302:英语中所有形容词都可以用adj.+of+n.这种形式吗?还是只有个别形容词才有这种用法呢? -
郗泻19785593444…… 这个形式一般用于形容人的性格,对象一般是人.比如:It's kind of you to help me.这种形式可改写为:You are kind to help me. adj.+for+n.+to do 则范围较大,可以是人,可以是物,比如:It's easy for me to solve the problem. 这种句式怎么不能改成上一种句式,只能改成:To solve the problem is easy for me.

@伏胥1302:do not worry i have a - way to solve the probiem 我等着用! - 作业帮
郗泻19785593444…… [答案] another 另一种方法

@伏胥1302:在Matlab中用什么函数求解非线性方程的根?写出求解如下非线性方程根的Matlab代码. x^2+exp(x) - 3=0 -
郗泻19785593444…… 利用solve函数,其格式为:a=solve('等式')代码如下:a=solve(' x^2+exp(x)-3=0')结果a = 0.83448...

@伏胥1302:matlab 中关于solve函数应用 -
郗泻19785593444…… clc;clear; syms w Rm=66.6; C0=629e-15; Cm=7.3e-15;Lm=113e-6; j=sqrt(-1); w=solve(1./((1./(j.*w.*Cm)+j.*w*Lm+Rm+1./(j.*w*C0))./(1./(j.*w*C0).*(1./(j.*w*Cm)+j.*w*Lm+Rm)))-1./Rm',w)

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