cos（x+y）
@滑扶620：cos(x+y)等于什么 -
宇邢19752939060…… cos(x+y)=cosxcosy-sinxsiny
@滑扶620：cos(x+y)=?sin(x+y)=?如题 - 作业帮
宇邢19752939060…… [答案] cos(x+y)=cosxcosy-sinxsiny sin(x+y)=sinxcosy+cosxsiny
@滑扶620：已知y(x),求y'.函数y=cos(x+y) -
宇邢19752939060…… y = cos(x+y) y' = -sin(x+y) . (1+y')(1+sin(x+y) )y'= -sin(x+y) y'= -sin(x+y)/(1+sin(x+y) )
@滑扶620：xy=cos(x+y) 求Y关于X的导数 -
宇邢19752939060…… xy=cos(x+y) 两边对x求导 y+xy'=-sin(x+y)·(1+y') y'[x+sin(x+y)]=-y-sin(x+y) y'=-[y+sin(x+y)]/[x+sin(x+y)]
@滑扶620：已知x,y是实数且满足sinx*cosy=1,则cos(x+y)= - 作业帮
宇邢19752939060…… [答案] sinx*cosy=1 sinx=cosy=1或sinx=cosy=-1 cosx=siny=0 因此cos(x+y)=cosxcosy-sinxsiny=0
@滑扶620：cos(x+y)的导数怎么求 - 作业帮
宇邢19752939060…… [答案] 对x求偏导,得 -sin(x+y) 对y求得, -sin(x+y)
@滑扶620：cos(x+y)的展开式 -
宇邢19752939060…… cosxcosy-sinxsiny
@滑扶620：求下列隐函数的导数 y=cos(x+y) - 作业帮
宇邢19752939060…… [答案] y'=[cos(x+y)]'=-sin(x+y)*(1+y')=-sin(x+y)+-sin(x+y)*y' 把含y'的部分移到等式的右边,所以: y'=-sin(x+y)/1+sin(x+y)
@滑扶620：数学公式:cos(x+y)=? sin(x+y)=?
宇邢19752939060…… cos(x+y)=cosxcosy-sinxsiny sin(x+y)=sinxcosy+cosxsiny
@滑扶620：cos(x+y)*cos(x - y)=cos*cosx+sin*siny -
宇邢19752939060…… cos(x+y)=cosx*cosy-sinx*siny cos(x-y)=cosx*cosy+sinx*siny 则cos(x+y)*cos(x-y) =(cos*cosx)*(cos*cosy) - (sin*sinx)*(sin*siny) =(cos*cosx)*(1-sin*siny) - (1-cos*cosx)*(sin*siny) =cos*cosx - (cos*cosx)*(sin*siny) - sin*siny + (cos*cosx)*(sin*siny) =cos...
宇邢19752939060…… cos(x+y)=cosxcosy-sinxsiny
@滑扶620：cos(x+y)=?sin(x+y)=?如题 - 作业帮
宇邢19752939060…… [答案] cos(x+y)=cosxcosy-sinxsiny sin(x+y)=sinxcosy+cosxsiny
@滑扶620：已知y(x),求y'.函数y=cos(x+y) -
宇邢19752939060…… y = cos(x+y) y' = -sin(x+y) . (1+y')(1+sin(x+y) )y'= -sin(x+y) y'= -sin(x+y)/(1+sin(x+y) )
@滑扶620：xy=cos(x+y) 求Y关于X的导数 -
宇邢19752939060…… xy=cos(x+y) 两边对x求导 y+xy'=-sin(x+y)·(1+y') y'[x+sin(x+y)]=-y-sin(x+y) y'=-[y+sin(x+y)]/[x+sin(x+y)]
@滑扶620：已知x,y是实数且满足sinx*cosy=1,则cos(x+y)= - 作业帮
宇邢19752939060…… [答案] sinx*cosy=1 sinx=cosy=1或sinx=cosy=-1 cosx=siny=0 因此cos(x+y)=cosxcosy-sinxsiny=0
@滑扶620：cos(x+y)的导数怎么求 - 作业帮
宇邢19752939060…… [答案] 对x求偏导,得 -sin(x+y) 对y求得, -sin(x+y)
@滑扶620：cos(x+y)的展开式 -
宇邢19752939060…… cosxcosy-sinxsiny
@滑扶620：求下列隐函数的导数 y=cos(x+y) - 作业帮
宇邢19752939060…… [答案] y'=[cos(x+y)]'=-sin(x+y)*(1+y')=-sin(x+y)+-sin(x+y)*y' 把含y'的部分移到等式的右边,所以: y'=-sin(x+y)/1+sin(x+y)
@滑扶620：数学公式:cos(x+y)=? sin(x+y)=?
宇邢19752939060…… cos(x+y)=cosxcosy-sinxsiny sin(x+y)=sinxcosy+cosxsiny
@滑扶620：cos(x+y)*cos(x - y)=cos*cosx+sin*siny -
宇邢19752939060…… cos(x+y)=cosx*cosy-sinx*siny cos(x-y)=cosx*cosy+sinx*siny 则cos(x+y)*cos(x-y) =(cos*cosx)*(cos*cosy) - (sin*sinx)*(sin*siny) =(cos*cosx)*(1-sin*siny) - (1-cos*cosx)*(sin*siny) =cos*cosx - (cos*cosx)*(sin*siny) - sin*siny + (cos*cosx)*(sin*siny) =cos...
