∫（sinx）^2dx
@冷月6722：求不定积分——∫sinx^2dx - 作业帮
阎冯18228833968…… [答案] ∫(sinx)^2dx=∫(1-cos2x)/2dx=x/2-1/4sin2x ∫sin(x^2)dx求不出来
@冷月6722：∫(sinx)^2dx - 作业帮
阎冯18228833968…… [答案] ∫(sinx)^2dx =1/2∫(1-cos2x)dx =x/2-sin2x/4+C
@冷月6722：求解∫(sinx)^2dx - 作业帮
阎冯18228833968…… [答案] 原式=∫(1-cos(2x))/2dx =1/2∫dx-1/2∫cos(2x)dx =x/2-1/4∫cos(2x)d(2x) =x/2-sin(2x)/4+C
@冷月6722：求∫(sinx)^2dx和(sinx)^2的原函数. -
阎冯18228833968…… ∫(sinx)^2dx=∫(1-cos2x)\2dx=x\2-sin2x\4+C 对于上下限为0和π的定积分,值为π\2
@冷月6722：∫x(sinx)^2dx用分部积分法求 - 作业帮
阎冯18228833968…… [答案] ∫x(sinx)^2dx=(1/2)∫x(1-cos2x)dx=(1/4)x^2-(1/2)∫xcos2xdx=(1/4)x^2-(1/4)∫xdsin2x=(1/4)x^2-(1/4)xsin2x +(1/4)∫sin2x dx=(1/4)x^2-(1/4)xsin2x -(1/8)cos2x + C
@冷月6722：∫x(sinx)^2 dx 怎么解? -
阎冯18228833968…… ∫x(sinx)^2dx=∫x(1-cos2x)/2dx=x^2/4-xsin2x/4+∫sin2x/4dx=x^2/4-xsin2x/4-cos2x/8+C分部后尽量使积分号后只剩下代数函数或三角函数而整数次幂函数有有限...
@冷月6722：求积分∫x(sinx)^2dx -
阎冯18228833968…… 分部积分法 ∫x(sinx)^2dx=sin(x)^2/4 - (x*sin(2*x))/4 + x^2/4
@冷月6722：求定积分∫x/(sinx)^2dx上限为3/π下限为4/π, - 作业帮
阎冯18228833968…… [答案] 遇到三角函数考虑万能公式.∫x/(sinx)^2dx=∫x/[(1-cos2x)/2]dx=∫2x/(1-cos2x)dx=∫2x/[1-(1-tgxtgx)/(1+tgxtgx)]dx=∫2x(1+tgxtgx)/(2tgxtgx)dx=∫[x/(tgxtgx)]d(tgx) (tgx)'=(1+tgxtgx)=-x/tgx +∫(1/tgx)dx =-x/...
@冷月6722：求不定积分∫x⁵sinx^2dx - 作业帮
阎冯18228833968…… [答案] ∫x⁵(sinx)^2dx=∫x⁵(1/2)(1-cos2x) dx =(1/2)[ ∫x⁵dx-∫x⁵cos2x) dx] =(1/2)[ (x^6)/6-∫x⁵cos2x) dx] =(x^6)/12-(1/2) ∫cos2x) d[(x^6)/6] =(x^6)/12-(1/2) ∫cos2x) d[(x^6)/6] x⁵=x^5 分部积分,就可以了,不好打,你自己去算一下好吗?
@冷月6722：∫x(sinx)^2dx= -
阎冯18228833968…… e^x(sinx)^2=e^x[(1-cos2x)/2]=e^x/2-e^xcos2x/2.(e^xsin2x)'=2(cos2x)e^x e^xsin2x (e^xcos2x)'=-2(sin2x)e^x e^xcos2x.故可得:2(e^xsin2x)' (e^xcos2x)'=5(cos2x)e^x.则e^xcos2x/2=[2(e^xsin2x)' (e^xcos2x)']/10.故e^x(sinx)^2=e^x/2-[2(e^xsin2x)' (...
阎冯18228833968…… [答案] ∫(sinx)^2dx=∫(1-cos2x)/2dx=x/2-1/4sin2x ∫sin(x^2)dx求不出来
@冷月6722：∫(sinx)^2dx - 作业帮
阎冯18228833968…… [答案] ∫(sinx)^2dx =1/2∫(1-cos2x)dx =x/2-sin2x/4+C
@冷月6722：求解∫(sinx)^2dx - 作业帮
阎冯18228833968…… [答案] 原式=∫(1-cos(2x))/2dx =1/2∫dx-1/2∫cos(2x)dx =x/2-1/4∫cos(2x)d(2x) =x/2-sin(2x)/4+C
@冷月6722：求∫(sinx)^2dx和(sinx)^2的原函数. -
阎冯18228833968…… ∫(sinx)^2dx=∫(1-cos2x)\2dx=x\2-sin2x\4+C 对于上下限为0和π的定积分,值为π\2
@冷月6722：∫x(sinx)^2dx用分部积分法求 - 作业帮
阎冯18228833968…… [答案] ∫x(sinx)^2dx=(1/2)∫x(1-cos2x)dx=(1/4)x^2-(1/2)∫xcos2xdx=(1/4)x^2-(1/4)∫xdsin2x=(1/4)x^2-(1/4)xsin2x +(1/4)∫sin2x dx=(1/4)x^2-(1/4)xsin2x -(1/8)cos2x + C
@冷月6722：∫x(sinx)^2 dx 怎么解? -
阎冯18228833968…… ∫x(sinx)^2dx=∫x(1-cos2x)/2dx=x^2/4-xsin2x/4+∫sin2x/4dx=x^2/4-xsin2x/4-cos2x/8+C分部后尽量使积分号后只剩下代数函数或三角函数而整数次幂函数有有限...
@冷月6722：求积分∫x(sinx)^2dx -
阎冯18228833968…… 分部积分法 ∫x(sinx)^2dx=sin(x)^2/4 - (x*sin(2*x))/4 + x^2/4
@冷月6722：求定积分∫x/(sinx)^2dx上限为3/π下限为4/π, - 作业帮
阎冯18228833968…… [答案] 遇到三角函数考虑万能公式.∫x/(sinx)^2dx=∫x/[(1-cos2x)/2]dx=∫2x/(1-cos2x)dx=∫2x/[1-(1-tgxtgx)/(1+tgxtgx)]dx=∫2x(1+tgxtgx)/(2tgxtgx)dx=∫[x/(tgxtgx)]d(tgx) (tgx)'=(1+tgxtgx)=-x/tgx +∫(1/tgx)dx =-x/...
@冷月6722：求不定积分∫x⁵sinx^2dx - 作业帮
阎冯18228833968…… [答案] ∫x⁵(sinx)^2dx=∫x⁵(1/2)(1-cos2x) dx =(1/2)[ ∫x⁵dx-∫x⁵cos2x) dx] =(1/2)[ (x^6)/6-∫x⁵cos2x) dx] =(x^6)/12-(1/2) ∫cos2x) d[(x^6)/6] =(x^6)/12-(1/2) ∫cos2x) d[(x^6)/6] x⁵=x^5 分部积分,就可以了,不好打,你自己去算一下好吗?
@冷月6722：∫x(sinx)^2dx= -
阎冯18228833968…… e^x(sinx)^2=e^x[(1-cos2x)/2]=e^x/2-e^xcos2x/2.(e^xsin2x)'=2(cos2x)e^x e^xsin2x (e^xcos2x)'=-2(sin2x)e^x e^xcos2x.故可得:2(e^xsin2x)' (e^xcos2x)'=5(cos2x)e^x.则e^xcos2x/2=[2(e^xsin2x)' (e^xcos2x)']/10.故e^x(sinx)^2=e^x/2-[2(e^xsin2x)' (...
